> > $("#div").call()
> >
> > tries to call the "call" method on $, but since there is no "call"
> > method (that I know of), it's not working.
>
> Actually, there is:
>
http://developer.mozilla.org/en/docs/Core_JavaScript_1.5_Reference:Global_Ob
jects:Function:call
>
> Using call or apply is another approach to solving this type
> of problem, but you have to be careful to pass in the
> appropriate "thisArg", which in this case would be the jQuery
> object itself.
The return value from $() isn't a function and doesn't have a call method.
In any case, Blair's code is the way to do it:
$("#div")[call]();
You can test this by going to www.visualjquery.com and paste this into the
FireBug console command line (click after the >>>):
var call = 'hide'; $('div')[call]();
:-)
-Mike
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