Thanks all for the help

http://www.cyberlot.net/demos/phpjquery/

Is the result of what I am playing with, a sort of integration between 
jquery and php, although my javascript code is not up to par so it might 
be a little messy

Michael Geary wrote:
>>> $("#div").call()
>>>
>>> tries to call the "call" method on $, but since there is no "call" 
>>> method (that I know of), it's not working.
>> Actually, there is:
>>
> http://developer.mozilla.org/en/docs/Core_JavaScript_1.5_Reference:Global_Ob
> jects:Function:call
>> Using call or apply is another approach to solving this type 
>> of problem, but you have to be careful to pass in the 
>> appropriate "thisArg", which in this case would be the jQuery 
>> object itself.
> 
> The return value from $() isn't a function and doesn't have a call method.
> 
> In any case, Blair's code is the way to do it:
> 
> $("#div")[call]();
> 
> You can test this by going to www.visualjquery.com and paste this into the
> FireBug console command line (click after the >>>):
> 
> var call = 'hide'; $('div')[call]();
> 
> :-)
> 
> -Mike
> 
> 
> _______________________________________________
> jQuery mailing list
> [email protected]
> http://jquery.com/discuss/
> 


-- 
Richard Thomas - CEO
Cyberlot Technologies Group Inc.
507.398.4124 - Voice

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