On Mon, 16 Oct 2006, Michael Geary wrote:
> The return value from $() isn't a function and doesn't have a call method.
>
> In any case, Blair's code is the way to do it:
>
> $("#div")[call]();
Right - I should have been more clear. To use call/apply, you'd have to do
it like this:
var obj = $('#div');
var meth = 'hide';
obj[meth].call(obj, 'slow');
var args = ['slow'];
obj[meth].apply(obj, args);
This probably isn't useful for the original poster's question, but it's
good to know in many cases when you're trying to resolve method calls
dynamically.
Dave
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