The model is simplified, but I assume that (B)
votes will be counted by "divining the voter's
intent" through chance imperfections in the
ballots. Thus the probability is 0.50.
Duncan Murdoch wrote:
>
> On Sat, 18 Nov 2000 22:49:41 -0500, Bob Wheeler <[EMAIL PROTECTED]>
> wrote:
>
> >There are two possibilities: (A) a vote was
> >attempted; (B) no vote was attempted. Let us
> >assume that for (A) the probability of a Gore vote
> >is 0.62, and 0.50 for (B),
>
> If no vote was attempted, then surely the probability that a vote for
> Gore was attempted is 0, not 0.50.
>
> Duncan Murdoch
--
Bob Wheeler --- (Reply to: [EMAIL PROTECTED])
ECHIP, Inc.
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