CF, You wrote (Fri.May 28):
Surely sharing up the time between the top-cycle candidates is the same sort of problem as sharing voting powerAs far as finding a time share goes, here's what I had in mind: Divide each term into sub-terms of equal length (say, six months). For X and Y, if X wins by Schulze, and Y is the candidate who, apart from X, loses the fewest comparisons of the strongest beatpaths, X and Y are the winners of the election. For X and Y, if X and Y are winners, use the strength of the beatpath from X to Y and the strength of the beatpath from Y to X as input, and use the Sainte-Lague formula to allocate the sub-terms.
between proxies, nothing complicated. Each ballot contributes one vote to the single top-cycle candidate it ranks
above the others, or equal fractions of a vote that sum to 1 to each of the top-cycle candidates it votes in equal
place above the others. Then the time in office for each of these top-cycle (or Shwartz set) candidates is allocated
in proportion to these tallies.
Chris Benham
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