Obviously though, if A has 8 pairwise wins, B has 7, and everyone else has less.....A will be the winner no matter what, right? Regardless of how close A's wins are and how large B's majorities are?
If that isn't true than I must totally misunderstand the concept of a Condorcet winner.
What system would you prefer? I'm a tad confused, because I thought all well-known Condorcet methods begin with a pairwise matrix.
-rob
On 11/16/05, Paul Kislanko <[EMAIL PROTECTED]> wrote:
"Candidates A, B and C all have 8 pairwise wins. D has 7. Could D still be chosen as the winner by any "reasonable" method? "Sure. D's 7 pairwise wins could be by a large enough majority that the "extra" pairwise win that A, B, and C have over the fringe candidate that beats D by 1 vote makes the "8" vs "7" irrelevant.This is kind of why I don't like any counting method that BEGINS with the pairwise matrix. Some systems would eliminated D when all of A, B, and C are real dogs that no majority likes.
---- election-methods mailing list - see http://electorama.com/em for list info
