Ok, I see what you are saying.  If there is a condorcet winner, that candidate will have more pairwise wins than any other candidate.  But just because someone has more pairwise wins does not make that candidate the condorcet winner.  Fair enough.  Thanks.

On 11/16/05, Scott Ritchie <[EMAIL PROTECTED] > wrote:
This is only guaranteed if there are 9 candidates, in which case A is
the condorcet winner.  Otherwise both A, B, and another could end up in
the Smith set.

-Scott Ritchie
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