Dear Mike,
1. What is the value of your expression when a = 0?
2. What role do you see the constant 1/e as playing?
Thanks.
Joe
On Jan 21, 2007, at 12:11 PM, Michael Ossipoff wrote:
Bias-Free is a divisor method, in the strictest sense of the word.
You know
how the divisor methods work, so I won't go into that, except to
say that
they all choose a rounding point between consecutive integers a &
b, by a
formula that specifies a function of a and b.
For example, with Webster the function is (a+b)/2. With Hill it's
sqr(a*b).
With Jefferson it's b. With Adams it's a.
So, with Bias-Free, it's ((b^b)/(a^a))(1/e).
Mike Ossipoff
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Joseph Malkevitch
Department of Mathematics
York College (CUNY)
Jamaica, New York 11451
Phone: 718-262-2551 (Voicemail available)
My new email is:
[EMAIL PROTECTED]
web page:
http://www.york.cuny.edu/~malk
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