Dear Mike, Joe--
You wrote: 1. What is the value of your expression when a = 0? I reply: It's 1/e. I don't remember the details of the derivation of that right now, and my e-mails have to be sent quickly, because the modem shuts down. Maybe between 0 and 1 it was an improper integral evaluating to 1/e. 2. What role do you see the constant 1/e as playing? I reply: It's just part of the formula that comes up when you solve for the rounding point. I can't explain why that is. But, in the 1st cycle, R is 1/e, and then in later cycles it gets multiplied by (b^b)/(a^a). Mike Ossipof ---- election-methods mailing list - see http://electorama.com/em for list info
