Here's my first attempt. Let's use modified Borda. The points can be
"balanced" e.g. by using square root.
X>Y>Z => (2, 1, 0) => (1.4, 1, 0)
X>Y=Z => (2, 1, 1) => (1.4, 1, 1)
55 A>C>B
45 B>C>A
A = 55 * 1.4 + 45 * 0.0 = 77.8
B = 55 * 0.0 + 45 * 1.4 = 63.6
C = 55 * 1.0 + 45 * 1.0 = 100.0
Juho
P.S. You didn't tell what the method should do with 55: A 100, C 20,
B 0, 45: B 100, C 20, A 0 :-)
On Aug 22, 2007, at 9:55 , Jobst Heitzig wrote:
A common situation: 2 factions & 1 good compromise.
The goal: Make sure the compromise wins.
The problem: One of the 2 factions has a majority.
A concrete example: true ratings are
55 voters: A 100, C 80, B 0
45 voters: B 100, C 80, A 0
THE CHALLENGE: FIND A METHOD THAT WILL ELECT THE COMPROMISE (C)!
The fine-print: voters are selfish and will vote strategically...
Good luck & have fun :-)
Jobst
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