There is a theoritical NSA program on the ETS website that will calculate the 
NSA for any given distance and scan height. I used it to generate numbers for a 
compliant 3m site (1 to 4m recieve scan height) and then ran the numbers with 
the transmit and recieve antenna heights at something like 30 meters. The 
difference was a nominal 6dB. 
 
Bob R.

--- On Thu, 12/22/11, Sundstrom, Michael <[email protected]> 
wrote:


From: Sundstrom, Michael <[email protected]>
Subject: RE: [PSES] Semi-Anechoic Chamber Question - Correction Factor
To: "Bill Owsley" <[email protected]>, "[email protected]" 
<[email protected]>
Date: Thursday, December 22, 2011, 8:54 AM







Bill,
I’d guess 6dB as in voltage, with dBuV being used. 
 

 
Michael Sundstrom
OHD / TREQ Dallas
Electronic Lab Analyst, EMC Lead
2170 French Settlement Rd, Suite B
Dallas, Texas  75212
(214) 579 6312
(940) 390 3644c
KB5UKT
 
Albert Einstein once said, "The definition of insanity is doing the same thing 
over and over again and expecting different results".
 


From: Bill Owsley [mailto:[email protected]] 
Sent: Wednesday, December 21, 2011 11:02 PM
To: [email protected]
Subject: Re: [PSES] Semi-Anechoic Chamber Question - Correction Factor
 


Go back, way back, to the paper by pate, german, smith, on the NSA.
Go through all the details and calculations and surmise that there is the 
direct path, and the reflected path.
The reflected path adds, or not, to the direct path, depending on wavelength 
(phase at receive antenna) and distance between antennas.
A scan up to 4 meters will generally cover the apparent phase shift at the 
lower frequencies such that a "maximum" is recorded.
This scan will certainly cover the apparent phase shift of higher freq's.
The reflected wave verses the direct wave, will have a longer distance and thus 
a little more loss. In the worst case, it can be neglected.
It will also suffer some loss at the reflecting surface, generally assumed to 
be a "perfect" boundary since it is unknown but defined as metal.
Thus, the received voltage received via a direct path added with a reflected 
path, assuming no distance or reflection loss, would be 6 dB higher than the 
direct path alone.  This direct path alone is the assumed field measured in a 
FAC, neglecting any chamber anomalies.
Or is it 3 dB higher?? as in power?

 





From: "Grasso, Charles" <[email protected]>
To: Jim Hulbert <[email protected]>; "[email protected]" 
<[email protected]> 
Sent: Wednesday, December 21, 2011 4:29 PM
Subject: RE: Semi-Anechoic Chamber Question - Correction Factor







Professor Leferink published a nice paper that proposed a different correction
factor for a SAC to a FAC. I tried to track it down but had no luck.

 


Best Regards
Charles Grasso
Compliance Engineer
Echostar Communications
(w) 303-706-5467
(c) 303-204-2974
(t) [email protected]
(e) [email protected]

(e2) [email protected]

 



From: [email protected] [mailto:[email protected]] On Behalf Of Jim Hulbert
Sent: Monday, December 19, 2011 2:27 PM
To: [email protected]
Subject: RE: Semi-Anechoic Chamber Question

 

Thank you everyone for the helpful feedback.  The consensus is clearly: Save my 
back and leave the absorber and ferrite tiles in place.  Compare radiated 
emissions measurements in the chamber to those on the OATS (several suggested a 
comb generator for this purpose).  Assign an adjustment factor to the chamber 
measurements to correlate as closely as possible to the OATS measurements (6dB 
has been suggested as a reasonable factor, although I need to confirm this 
through my own measurements).

 

Jim

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