In message <[email protected]>, dated Fri, 31 Jul 2015,
John Woodgate <[email protected]> writes:
Is there a standard equation for calculating the reflection angle on
an OATS/SAC with a varying height antenna? Or can someone give me some
pointers to help me figure it out myself
Make a drawing. The only odd bit is that cotangents occur.
Height of Tx = T, height of Rx = R. Distance between antennas = S
Angle between incident ray and plane = angle between reflected ray and
plane = alpha.
T*COT[alpha] + R*COT[alpha] = S
COT[alpha] = S/(T+R)
Angle of reflection = 180-2[alpha]
That is the angle between the incident and reflected rays. The
conventional angle of incidence (and therefore the conventional angle of
reflection) is half that.
Call that angle beta. Then TAN[beta] = S/(T+R)
The physical path length is (T+R)COSEC[alpha] or (T+R)SEC[beta].
--
OOO - Own Opinions Only. With best wishes. See www.jmwa.demon.co.uk
When I turn my back on the sun, it's to look for a rainbow
John Woodgate, J M Woodgate and Associates, Rayleigh, Essex UK
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