On Fri, Oct 23, 2009 at 11:33:15AM -0700, Peter C. Wallace wrote: > Its still is a quadrature decoder but it only counts on one edge (rising edge > of A in this case, state of B on rising edge of A determines direction)
If this is true, it is not a correct decoding. Imagine B is high, and A goes high/low/high/low/high/low correct decoding is +1, -1, +1, -1, ... The scheme you suggest gives an incorrect +1, +1, +1, ... ------------------------------------------------------------------------------ Come build with us! The BlackBerry(R) Developer Conference in SF, CA is the only developer event you need to attend this year. Jumpstart your developing skills, take BlackBerry mobile applications to market and stay ahead of the curve. Join us from November 9 - 12, 2009. Register now! http://p.sf.net/sfu/devconference _______________________________________________ Emc-users mailing list Emc-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/emc-users
