This is the formula I used to figure INPUT SCALE 5000 * 28/14 * 5 counts/inch = 
50,000 counts/inch but this does not work.
I found by trial and error that having an INPUT SCALE of 1000000 works. I am 
confused about this.
This is a differential encoder, "heidenhain rod 476, 5000"
Just trying to wrap my head around this.

Regards,Bruce

--- On Wed, 11/30/11, Sebastian Kuzminsky <s...@highlab.com> wrote:

From: Sebastian Kuzminsky <s...@highlab.com>
Subject: Re: [Emc-users] How do I cipher "INPUT SCALE"
To: "Enhanced Machine Controller (EMC)" <emc-users@lists.sourceforge.net>
Date: Wednesday, November 30, 2011, 5:41 PM

On Nov 30, 2011, at 15:31 , Bruce Klawiter wrote:
> OK once again the simplest thing is driving me crazy.
> How do I figure out what the "input scale" should be in the ini file for the 
> 3 axes.
> 5000 count per rev encoder on servo, 14 tooth gear on servo motor, 28 tooth 
> gear on lead screw, lead screw is 5tpi


INPUT_SCALE converts encoder counts to machine units.  Since you gave your lead 
screw pitch in imperial units, I assume you want your machine units to be 
inches.

So you have:

5000 counts/motor-rev * 28 motor-rev/14 lead-screw-rev * 5 lead-screw-revs/inch

Which is

5000 * 28/14 * 5 counts/inch = 50,000 counts/inch

So your INPUT_SCALE should be 50000

I think.

-- 
Sebastian Kuzminsky


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