Lol oops my math is still wrong.
anyways the heidenhain does specify by line count.
Chris M

> From: chrisinnana...@hotmail.com
> To: emc-users@lists.sourceforge.net
> Date: Mon, 5 Dec 2011 20:00:57 +0000
> Subject: Re: [Emc-users] How do I cipher "INPUT SCALE"
> 
> 
> 
> 
> > Date: Mon, 5 Dec 2011 11:30:26 -0800
> > From: bmkl...@yahoo.com
> > To: emc-users@lists.sourceforge.net
> > Subject: Re: [Emc-users] How do I cipher "INPUT SCALE"
> > 
> > This is the formula I used to figure INPUT SCALE 5000 * 28/14 * 5 
> > counts/inch = 50,000 counts/inch but this does not work.
> > I found by trial and error that having an INPUT SCALE of 1000000 works. I 
> > am confused about this.
> > This is a differential encoder, "heidenhain rod 476, 5000"
> > Just trying to wrap my head around this.
> > 
> > Regards,Bruce
> 
> Heidenhain specifies LINECOUNT of 5000.
> Encoder reads Quadrature pulses (unless set otherwise)
> 
> so a line count of 5000 x 4 quadrature edges per line = 20000 pulses
> 
> also you probably have the gear ratio backwards 
> 
> so 20000 * 14/28 * 5 = 50,000
> 
> Chris M
>                                         
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