On Sunday 02 March 2014 17:21:41 Peter C. Wallace did opine:

> On Sun, 2 Mar 2014, Gene Heskett wrote:
> > Date: Sun, 2 Mar 2014 16:10:23 -0500
> > From: Gene Heskett <[email protected]>
> > Reply-To: "Enhanced Machine Controller (EMC)"
> > 
> >     <[email protected]>
> > 
> > To: "Enhanced Machine Controller (EMC)"
> > <[email protected]> Subject: [Emc-users] This sparkfun
> > opto kit,
> > 
> >     2 channel. Question re led polarities.
> > 
> > Greetings;
> > 
> > leds are something I'll have to plead less than a full understanding
> > of.
> > 
> > So, if I connect these 2 channels of this sparkfun kit such that the
> > anode of one is connected to the cathode of the other, effectively
> > placing them in parallel, add a current limiter in series with the
> > common of one end, do I need to also put in a reverse voltage
> > protection diode, or will the one that needs to light up, will light
> > up without being shorted out by the other polarity led across it?
> > 
> > The C1G can put out sufficient currant (24 ma) but I believe its
> > programming jumpers cannot allow both polarities, its a one or the
> > other deal per data line, so I'll have to invert the signal to get
> > the opposite drive external to the C1G, but that doesn't seem to be a
> > show stopper.
> > 
> > The idea is to have the 2 optos outputs in totem pole for a
> > bidirectional drive +12 volts or 0 volts, both active on an exclusive
> > basis into the Gemini controller.
> > 
> > The question is, do I need to polarity protect the leds in the opto
> > package?  The pdf I downloaded on the opto package is less that
> > informative on this particular detail.
> > 
> > Cheers, Gene
> > 
> > NOTICE: Will pay 100 USD for an HP-4815A defective but
> > complete probe assembly.
> 
> Back to back LEDs should work fine (usually they have a 5V max reverse
> voltage spec and about 1.1V forward drop so one protects the other. but
> back to back LEDs need a bipolar source (say 2 equal resistors for a
> 2.5V reference/current limit and a push pull 5V output)
> 
> 
> If you have a 5V push-pull output, another way would be to connect this
> output to Cathode1 and Anode2 and connect Anode1 to 5V through a
> resistor and Cathode2 to ground through another resistor.
> 
Thanks Peter, that will solve the single ended signal source problem too at 
the cost of another conductor from the 5 volts in the C1G.

But the i limiting R can also be in the common signal input line I'd 
assume?  Or will that common voltage drop eat my lunch? OTOH, resistors in 
500 packs from the shack are cheap. :)

Cheers, Gene
-- 
"There are four boxes to be used in defense of liberty:
 soap, ballot, jury, and ammo. Please use in that order."
-Ed Howdershelt (Author)
Genes Web page <http://geneslinuxbox.net:6309/gene>

NOTICE: Will pay 100 USD for an HP-4815A defective but
complete probe assembly.


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