On Sunday 02 March 2014 18:12:42 Peter C. Wallace did opine:

> On Sun, 2 Mar 2014, Gene Heskett wrote:
> >> If you have a 5V push-pull output, another way would be to connect
> >> this output to Cathode1 and Anode2 and connect Anode1 to 5V through
> >> a resistor and Cathode2 to ground through another resistor.
> > 
> > Thanks Peter, that will solve the single ended signal source problem
> > too at the cost of another conductor from the 5 volts in the C1G.
> > 
> > But the i limiting R can also be in the common signal input line I'd
> > assume?  Or will that common voltage drop eat my lunch? OTOH,
> > resistors in 500 packs from the shack are cheap. :)
> > 
> > Cheers, Gene
> > 
> > NOTICE: Will pay 100 USD for an HP-4815A defective but
> > complete probe assembly.
> 
> Sure, one resistor is fine for the second method. Slight advantage of
> two is that the LED drives can be individualy adjusted.
> 
Great, that will be the first cobble up test then when they have arrived,  
thanks Peter.

Cheers, Gene
-- 
"There are four boxes to be used in defense of liberty:
 soap, ballot, jury, and ammo. Please use in that order."
-Ed Howdershelt (Author)
Genes Web page <http://geneslinuxbox.net:6309/gene>

NOTICE: Will pay 100 USD for an HP-4815A defective but
complete probe assembly.


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