Przemek, the shield picks up stray energy from the suroundings. The 
inside of it is a faraday cage and free of electric fields, which is 
what we aim at. Now, as the shield has picked up the noise energy, 
(re)converting electromagnetic field energy to real voltage and current, 
it must get rid of it somewhere. This is most quickly done by a low 
resistance, i.e. low impedance, shorting the noise current to ground on 
the sending side without reaching the signal "consumer".
Sorry for answering late, I was on a short trip for the last days.
Peter


Am 18.03.2015 17:11, schrieb Przemek Klosowski:
> On Mon, Mar 16, 2015 at 11:34 AM, Peter Blodow <[email protected]> wrote:
>> Steve,
>> this is a good description of noise reduction by shielding. To make it
>> more exact, the shield should be grounded at the end where the lower
>> impedance is, mostly the signal source.
> This is opposite to what Steve said, which was to ground near the
> signals are consumed, which makes more sense to me because shield
> potentials, if any, have smaller chance of leaking through to the
> signal wires.
> >From the impedance point of view, I would also worry more about
> interference near high-impedance nodes rather than low-impedance
> nodes, just because smal currents result in larger voltages there.
>
> Can you summarize the rationale for your recommendation in the
> language of electromagnetics?
>


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