The one I have was made by Avenger Products, model 21400. Uses G13A batteries. The company appears to have been bought by Jewett-Cameron circa 2011 and this particular product discontinued.
Web archive! https://web.archive.org/web/*/http://www.avengerproducts.com:80/laser.asp Focus is adjustable to get the smallest dot at the aligning distance. Shine it up close at something and it makes a short line. Huh.The laser pointer I bought back when they first dropped to $10 was better than that, no adjustable focus but that could be remedied by sufficiently motivated use of a lathe. The thing to search for is a single emitter laser module. On Wednesday, September 26, 2018, 8:08:57 AM MDT, Gene Heskett <ghesk...@shentel.net> wrote: On Wednesday 26 September 2018 05:23:42 andy pugh wrote: > On Wed, 26 Sep 2018 at 06:13, Chris Albertson <albertson.ch...@gmail.com> wrote: > > On Tue, Sep 25, 2018 at 1:04 AM andy pugh <bodge...@gmail.com> wrote: > > > I can't help thinking that the way to determine the amount of > > > correction needed is to actually machine a test bar and measure > > > it. > > > > A laser beam is straighter than any bar. and is quicker and costs > > less. It may be straighter, but the ones I just bought for this, at a combined $85 for the 2of them, have 3 problems: The 1st being that it appears they are multiple emitter devices giveing an upclose beam that integrates to about a .5 by 1mm central image made up of individual beams a few microns apart. And the 2nd is axial alignment, combined with the beam spreading at 30" out, gives a bar of light at full intensity that is around 2mm wide by 4mm long, and describes a nearly 10 mm diameter circle on the target as the spindle rotates. Theres no way a 5mm square working area chip can work with that much off axis a beam. Its going to be clear off the imaging chip. The only way would be to rotate the spindle until the pattern is vertical, and drive the crossfeed to center the beam on the imager. Then rotate the spindle 180 degrees and using the crossfeed drive to recenter the image on the imager then calculate the center, doing this every 1/2 inch near the spindle because thats where the majority of the wear is. _______________________________________________ Emc-users mailing list Emc-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/emc-users