On Mar 23, 2012, at 9:48 AM, Russell Leggett wrote:
> ...
> That should probably not be legal but begs the question how does extension
> fit into hoisting. Would this work?
>
> class C extends B{...}
> class B extends A{...}
> class A{...}
>
> Desugaring extension into <| would force it back into an assignment
> expression again instead of a function declaration, so following that logic,
> only A would be hoisted in my last example, and so class C would fail.
A wouldn't initialize early either. If class C extends B is treated as const
C=B <| function() {} then for consisteny we must treat class A{}; as const
A=function() {}
>
> I think we should stick with const style hoisting. The restrictions are not
> very difficult and the result is cleaner.
exactly
Allen
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