On 11/26/2013 02:28 PM, Claude Pache wrote: >/ From the thread [1], I guess that parsing correctly the following thing would be obnoxious (at best)? />/ />/ (a = yield/b/g) =>* {} />/ />/ ---Claude / Indeed.And you can make even more obnoxious parses of the hypothetical combination of =>*, default parameters, and retroactive yield-scope: (a = yield/"/) =>* (/"/g) Are the two /"/'s regexps or is "/) =>* (/" a string token? Waldemar
Are you sure? The `(a = yield/b/g)` part is parsed at first as a parenthesised expression and only later (after the `=>` token) reinterpreted as an ArrowFormalParameters grammar production.
- André
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