Hello Lee
 
I agree with everything below
 
However this does not address when resistance varies by cell or module. 
 
Don Blazer
 
 
In a message dated 6/20/2013 1:02:59 P.M. Pacific Daylight Time,  
[email protected] writes:

Message:  7
Date: Thu, 20 Jun 2013 11:23:50 -0500
From: Lee Hart  <[email protected]>
To: Electric Vehicle Discussion List  <[email protected]>
Subject: Re: [EVDL] Resistance
Message-ID:  <[email protected]>
Content-Type: text/plain;  charset=ISO-8859-1; format=flowed

On 6/19/2013 7:07 PM,  [email protected] wrote:
> It still does not answer or address where  the energy comes from that was
> lost in raising the cell or cells with  the higher resistance over ambient
> temperature.

During  charging, the charger supplies more energy, since the pack 
voltage is  higher (due to the resistance).

Perfect 100v 100ah pack (with zero  resistance):
- Charger supplies 100v x 10a x 10h = 10kwh
-  Batteries get 10a x 10h = 100ah of charge

Same 100v 100ah pack, but  with resistance:
- Charger supplies 110v x 10a x 10h =  11kwh
- 1kwh of heat is produced in the resistance
-  Batteries get 10a x 10h = 100ah of charge

During discharge, the  batteries supply the same amount of energy, but 
some of it is burned up as  heat (in the cell resistance), rather than 
powering the  load.

Perfect 100v 100ah pack (with zero resistance):
-  Controller loads batteries 100v x 10a x 10h = 10kwh
- Batteries  deliver 10a x 10h = 100ah of charge

Same 100v 100ah pack, but with  resistance:
- Batteries sag to 90v under 10a load
- Load  gets 90v x 10a x 10h = 9kwh
- 1kwh of heat is produced in the  resistance
- Batteries still deliver 10a x 10h = 100ah of  charge

> As an example  NiMH cells in the past have a very high  self discharge
> rate. You can charge up a pack and they lose energy  while reaching a full
> charge. Cells that have higher resistance or are  in a higher state of  
charge
> lose more energy as heat then the  others. If you let the pack sit in a  
fully
> charged state they  self discharge and the energy loss produces heat.  
Enough
> that it  actually helps keep the pack warmer in the winter.

Both lead-acid and  nimh have "side" chemical reactions (gassing and 
heating) that can occur.  For nickel-based cells (NiCad, Nimh, NiFe) 
these side reaction starts  above 1.45 v/cell, and by 1.54v/cell this 
side reaction is consuming  essentially 100% of the applied current. For 
lead-acid, it starts above  2.27v/cell, and by 2.5v/cell the side 
reactions are consuming essentially  100% of the applied current.

The side reactions are strongly related to  voltage and temperature. A 
small increase in voltage or temperature causes  a dramatic increase in 
the current bypassed by them.

Lithium cells  (mostly) don't have these side reactions, so the 
self-discharge rate is  much lower. On the other hand, there is nothing 
short of destruction of  the cell to limit the voltage rise.

-- 
Don't worry about people  stealing your ideas. If your ideas are any 
good, you'll have to ram them  down people's throats. -- Howard Aiken
--
Lee A. Hart,  http://www.sunrise-ev.com/LeesEVs.htm
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