Don,

I am afraid that you still do not get it, because you are still thinking
about NiMH (which has large self-discharge, esp towards the top SoC)
while we were discussing Lithium-Ion technology that should have almost
no self-discharge.
Note that there are two types of resistance, easily mistaken and causing
exactly the confusion that we are dealing with here:

- Self-discharge of a cell can be modeled as a (large value) resistor in
parallel with the cell, causing a current to flow directly from cell
into this resistance, *not* through the other cells, so current can be
different in a series string of cells, due to current "escaping" the
series path via the parallel resistors of self-discharge. In good cells,
the self-discharge current is low (high resistance value).
- Internal resistance of a cell can be modeled as a (low value) resistor
in series with the cell, so all current flowing through the cell also
flows through the internal resistance. The only effect of internal
resistance is the voltage drop in the direction of the current, the
amount of current is still equal in all cells in a series string, cells
might show higher or lower voltage under load due to the voltage drop
across the internal resistance.

We were discussing Lithium-Ion cells, where the self-discharge is so low
that the current escaping the series string is neglible, so all cells
see the same current. But the voltage drop in the internal resistance
can be significant and vary per cell, due to abuse or defects.
Only in extreme cases will the self-discharge also come into play, but
then
you are talking about really bad or abused packs. I have one and I need
to
charge some cell independent from others due to current loss in
self-discharge. Still, it is good enough to survive several months as
long as I
do not discharge the pack too deep. I use this mostly as battery pack
for
my e-Bike.

Hope this clarifies,

Cor van de Water
Chief Scientist
Proxim Wireless Corporation http://www.proxim.com
Email: [email protected] Private: http://www.cvandewater.info
Skype: cor_van_de_water Tel: +1 408 383 7626


-----Original Message-----
From: [email protected] [mailto:[email protected]] On
Behalf Of [email protected]
Sent: Thursday, June 20, 2013 1:33 PM
To: [email protected]
Subject: [EVDL] Resistance

Bill & David and all
 
I am in total agreement and understand about the flow of current in
series. 
 
Each cell is delivered an equal amount of power. 
 
The electrons go through the pack equality so no cell receives more or  
less energy. 
 
The resistance losses I am addressing, do not change the volume of
current  
delivered to each cell in series. 
 
It is the differences between cells, which also include resistance,
which  
changes the capacity retained in the cells. Capacity retained in cells
can 
and is different if cells or modules lose a part of that energy at a
greater 
 rate then others during charging.
 
This is nothing new 
 
To balance a NiMH pack a common method is to over charge the pack with
the  
full cells bleeding energy as heat. The current is exactly the same to
each 
of  the cells but the NiMH chemistry is capable of losing a substantial

amount of energy as heat. The fully or nearly fully charged cells have
higher 
resistance readings and because of this create more heat then cells
still 
gaining capacity. 
 
As I stated before resistance in a cell is not a constant. As a cell  
reaches a full charge the resistance increases. I have measured this so
there is  
no doubt, cells with a higher state of charge lose a greater amount  of 
energy as heat. 
 
While I don't recommend others to do this. I have manually balanced a
pack  
by removing or adding capacity to modules while charging. When removing

capacity it basically has the same effect as resistance  differences in 
series, except instead of the energy lost as heat the  energy is
removed. Either 
way the energy is no longer retained in the module.  When needed I have 
adjusted the load to zero out the incoming capacity to this  module
while the 
rest gain. Each module in the pack was still  being charged at the same
rate 
and so of course there was no loss  or gain in any other modules. I
understand 
completely in series the amount of  energy delivered does not change.  
 
 
In the last 7 years I have been working mostly with  used NiMH modules
from 
several different manufacturers with EV pack  voltages of 300 to 420
volts. 
If I had only one method of selection in using  modules it would be 
resistance readings. I have gone though a 1000 used NiMH  modules and
the closer 
you can keep resistance readings the better your results  will be. 
 
If cells have even slight differences in resistance, they don't all heat
up 
 exactly equal on charge and discharge. 
 
Don Blazer
 
 
In a message dated 6/19/2013 11:30:57 P.M. Pacific Daylight Time,  
[email protected] writes:


Message: 12
Date: Wed, 19 Jun 2013 19:52:56 -0600
From:  Bill Dube <[email protected]>
To: Electric Vehicle Discussion  List <[email protected]>
Subject: Re: [EVDL]  Resistance
Message-ID:  <[email protected]>
Content-Type: text/plain;  charset=ISO-8859-1; format=flowed

The cells heat on both charge, and on  discharge. (Ohmic heating has no 
polarity.)

Again, no electrons are  lost. They all go around the entire circuit 
without losing a single one.  Each electron flips a chemical ion from
one 
plate to the other plate  through the electrolyte.

With Li-Ion cells, unless the electron is  forced  to flip the wrong ion

(like when you over charge, or over  discharge and damage the battery,) 
there is a one-to-one ratio to the  electron flow and the state of
charge.

Bill  D.
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