Thank you everyone for the great response so far.  I am still communicating
with a few Aliexpress sellers although it has been quite frustrating.  So
far none have been able to give me any documentation on these packs- cell
type and count, string info, bms used, etc.  I have been able to weed a few
out by reviews and overzealous claims.  Product weight seems to be a tell
tale as well, how can a pack weight half as much as other packs and have
the same claimed a/h rating?

After some more digging this weekend I have found a Canadian seller of used
Tesla packs.  I think I can get 2 x modules of 6s74p (444 cells) from a low
mileage 2015 P85D for around the same price as a 96v100ah pack on
Aliexpress.  I would still have to buy a BMS and likely a charger.  I have
saw some articles on cutting the bus bars and turning it them into 12s37p
packs so I could get 2 x 48v packs and 96 volts total so I can eliminate my
noisy gear set.  I could also buy 4 packs but that would be way more pack
that I need at this time.  Anyone ever hack a Tesla pack to make it 48
volts?

Cheers
Dan

On Sun, Mar 17, 2019 at 6:20 AM Steve Heath via EV <ev@lists.evdl.org>
wrote:

> Michael:  totally agree. At the cell level you are right and in the end
> the user has to take responsibility. The challenge facing people that a
> single Liion cell is not going to cut it so they have to be assembled
> into packs and that is where the differences start coming out. What
> follows is that cell level properties do not automatically
> follow/scale/apply to the battery pack.
>
> At the cell level Liion shows virtually zero  Peukerts effect. At the
> pack level with a BMS, it will. The cause is very different though.
>
> At the cell level, 0%age discharge is not damaging. At the pack level,
> cells can go out of balance and potentially short out. BMS will prevent
> the 0%age from being reached as part of the system level management
> strategy.
>
> At the cell level, there is nothing stopping Liion cells from being
> connected in parallel or series. At the pack level, parallel operation
> is not a problem but in series, the BMS can fail.
>
> At the cell level, you can extract all the capacity. At the pack level,
> this is difficult with the BMS applied. So if 100aH is the minimum
> needed in reality, a bigger capacity battery is needed.
>
> I think the problem is that we have become so used to treating cells
> like lego that it is easy to forget about the care and management side
> of Liion. Equally it can be very confusing when cell level and system
> level data/behaviour is compared because they can be almost
> contradictory which makes it very confusing to people trying to
> understand what is going on.
>
>
>
> On 17/03/2019 04:10, Michael Ross via EV wrote:
> > Steve, the ratings are per cell. WHat else is there to do?  No management
> > is needed as with a pack. Measuring the capacity of a cell is pretty
> > straightforward. It is up to the user to determine the needed capacity
> of a
> > pack and how to take care of it.
> >
> > On Sat, Mar 16, 2019 at 6:31 PM Steve Heath via EV <ev@lists.evdl.org>
> > wrote:
> >
> >> There are lies, damn lies and battery AH data.
> >>
> >> Yes you are right in that even with a "100aH Liion battery" I would
> >> derate it by 80% or so because of the BMS and so on.
> >> The problem with many Ah figures is that you do not know how they were
> >> measured. Is this with or without the BMS?
> >>
> >> Most companies take the aH from each cell in the series string and add
> >> them up. Some pluck a figure out of the air!
> >>
> >> 80% of the manufacturer figure is a good place to start but that might
> >> be a tad high in my experience with those size of currents.
> >>
> >> Steve
> >>
> >>
> >> On 16/03/2019 21:51, Dan Baker via EV wrote:
> >>> Wow, lots of learning here.  So with Lithium, a safe BMS cut-off
> >> typically
> >>> kicks around when there is less than 20% remaining? So the a/h ratings
> >>> typically (and when truthfully) displayed are actually 20% less?  100
> a/h
> >>> battery is typically only 80 a/h?  This is fine as I know you can't get
> >>> 100% of out lead either.  I looked up my SBS-170f lead's datasheet, to
> >> take
> >>> the cells to 1.80VPc (half discharged I believe) will happen with 116
> >> amps
> >>> for 1 hour.  This is recommended bottom voltage and I typically see
> that
> >>> with my boat as the draw is pretty constant when cruising.  To take the
> >>> leads all the way to near complete discharge (damaging but not
> >> exploding) -
> >>> 1.60 Vpc the amps for one hour is 125 amps so not much more.  So with a
> >> 200
> >>> ah pack I can expect about 1.6 hours of run time at 100 amps?   In
> >> reality
> >>> I think I can probably get closer to 2 hours if I keep the speed the
> same
> >>> and reduce the amps as the weight loss will dramatically reduce water
> >>> drag.
> >>>
> >>> On Sat, Mar 16, 2019 at 6:08 PM Bill Dube via EV <ev@lists.evdl.org>
> >> wrote:
> >>>> No Paul, Lee is indeed referring to the rate of discharge chart,
> >>>> however, he has chosen the cut-off to be _*3 volts*_, rather than the
> >>>> customary cut-off of_*2.5 volts*_. (No one uses a cut-off of 3 volts,
> >>>> that I am aware of. All the charts note that 2.5v cut-off is the
> >>>> standard for comparison. If we picked 3.5 volts as the cut-off, we
> would
> >>>> get a huge spread in the apparent capacity, but that would be silly.)
> >>>>
> >>>> You are correct that the 12 minute discharge (0.2C rate), the 0.5C
> rate,
> >>>> and the 1C rate all show the same capacity, 3.25 mA-hr. While the 2
> hour
> >>>> discharge (2C rate) shows a slightly elevated capacity of  3.350 mA.
> >>>>
> >>>>        I suspect that the faster rates had some unavoidable internal
> >>>> heating, (even though the case temperature was held at a constant 25
> >>>> degrees Celsius,) which tends to decrease the internal resistance, and
> >>>> tends to raise the terminal voltage under load, especially when the
> >>>> impedance rises near the end. Thus, the apparent capacity shift is
> quite
> >>>> likely due to increased internal temperature rather than ion
> diffusion.
> >>>>
> >>>>        Lead acid curves would have shown a much greater sensitivity to
> >> the
> >>>> discharge rate. Much greater. As I said earlier, the ions can diffuse
> >>>> perhaps 100 times more quickly in Li-Ion cells than in lead-acid
> cells,
> >>>> which makes the Puekert exponent very close to unity in Li_ion.
> Puekert
> >>>> is not really useful in Li_ion because the diffusion is so fast in
> >> Li-Ion.
> >>>> Bill D.
> >>>>
> >>>>
> >>>> On 3/17/2019 12:40 AM, paul dove via EV wrote:
> >>>>> That’s not what the spec sheet says. You are reading the graph for
> >>>> temperature variations. There is almost no difference due to discharge
> >>>> rates. 2C is 3250 and 0.5C is 3350 according to your spec sheet.
> >>>>> And lead acid batteries have a Puekert coefficient as low as 1.08.
> >>>>>
> >>>>> Sent from my iPhone
> >>>>>
> >>>>>> On Mar 15, 2019, at 9:14 AM, Steve Heath via EV <ev@lists.evdl.org>
> >>>> wrote:
> >>>>>> Peukert's law is not an actual law but an empirical formula that is
> >>>> based on actual physical measurements. It gives an approximate
> estimate
> >> of
> >>>> how much capacity can be obtained. The way that it is used is that the
> >>>> capacity is measured at different discharge rates to give a
> co-efficient
> >>>> that can then be applied to other batteries.  This is where the
> >> difficulty
> >>>> lies. The coefficient is taken by measurement and providing another
> >> battery
> >>>> is the same then the coefficient is applicable. If not and it isn't.
> >>>>>> The key point is that the discharge curves for li ion batteries do
> >> vary
> >>>> significantly depending on the load in real life according to the
> >>>> manufacturer data.  At the 0% soc end point, the capacities are the
> same
> >>>> (give or take). This is why the Peukerts coefficient is close to 1
> >> rather
> >>>> than 1.2 or higher for a lead acid battery. Hence the comment that it
> is
> >>>> not applicable. It is there but very small to be accurate.  However
> at a
> >>>> typical self preservation point e.g   cutoff voltage used by BMS, the
> >>>> capacities are different. As a result, there is a "Peukerts" effect
> >> where
> >>>> the amount of capacity that can be obtained is different depending on
> >> the
> >>>> discharge current. It is not the same Peukerts effect but the end
> >> result is
> >>>> the same. Discharge more, less capacity...
> >>>>>> The data sheet for a Panasonic 18650 shows this effect very well (
> >>>> https://www.batteryspace.com/prod-specs/NCR18650B.pdf ) where a cut
> off
> >>>> voltage of 3v gives a capacity of 2400mAh at 2c and 3300 mAh  at 0.2C
> >> .  At
> >>>> the 0% soc point they all come out at 3300 and 3400. So discharging to
> >> 0%
> >>>> soc, the discharge current is more or less irrelevant. Interestingly
> >> these
> >>>> results are taken at constant cell temperature where any overheating
> >>>> advantage is not applicable. Without seeing the complete paper that
> was
> >>>> referred to, it is difficult to know if any comparison with
> manufacturer
> >>>> data was made or whether tests were done at constant temperature and
> >> what
> >>>> the results were.
> >>>>>> Discharging to a lower 15-20% level to protect the battery, there
> is a
> >>>> big difference. If you want to get the best capacity out of a li ion
> >>>> battery with a BMS, either reduce the discharge rate or change the BMS
> >> to
> >>>> accept a lower cutoff voltage and risk battery damage.
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