On Friday, November 14, 2025 at 8:30:29 PM UTC-7 Alan Grayson wrote:

On Friday, November 14, 2025 at 7:42:23 PM UTC-7 Russell Standish wrote:

T(u,v) = uᵀMv where M is the matrix representation of T, and ᵀ is the 
transpose operator.


This is too succinct for me to understand your explanation. AG 


*Is the above how a tensor is generally evaluated? How would it be 
evaluated if*
*T has three independent variables, u,v,w? AG*

*If u and v are modeled as row matrices, then u transposed is a colum 
vector, and*
*the total result is a real number. But I don't think it's easy to show 
that this is the*
*same value obtained by modeling the tensor as a linear function of u and 
v. Offhand.*
*do you have a link for showing the equivalence?  Further, in the case of 
T(u), how is *
*the result a real number when using matrix notation? It looks like a 
vector when u*
*is modeled as a column vector. OTOH, I don't think we can model u as a row 
vector*
*to do the **calculation in this situation (or can we?). AG *


On Fri, Nov 14, 2025 at 05:12:46PM -0800, Alan Grayson wrote: 
> 
> 
> On Thursday, November 13, 2025 at 11:14:13 PM UTC-7 Russell Standish 
wrote: 
> 
> On Sat, Nov 08, 2025 at 05:25:16AM -0800, Alan Grayson wrote: 
> > In some treatments of tensors, they're described as linear maps. So, in 
> GR, if 
> > we have a linear map described as a 4x4 matrix of real numbers, which 
> operates 
> > on a 4-vector described as a column matrix with entries (ct, x, y, z), 
> which 
> > transforms to another 4-vector, what must be added in this description 
to 
> claim 
> > that the linear transformation satisfies the definition of a tensor? 
TY, 
> AG 
> 
> The operation of matrix multiplication is linear over the vectors on 
> the right hand side. 
> 
> Is that what you're missing? 
> 
> 
> Suppose T is a tensor which operates on vector v in some vector space. 
Then T 
> (v) 
> maps to a real number and is linear in v. If we change coordinates, v's 
> coordinates will 
> change but v remains the same, so T is invariant wrt coordinate 
> transformations. 
> Now let's look at the situation using matrix representation and assume 
we're 
> dealing 
> with a 4 dimensional spacetime manifold. Then T can be represented by a 
4x4 
> matrix, 
> and v can be represented as a column matrix with entries ct, x, y, z.  
When T 
> operates  
> on v, we get another column vector, and not a real constant! What am I 
doing 
> wrong?  
> Doesn't every tensor map to a real number? Also, if T is a function of 
two 
> vectors, T(u,v), 
> then using matrix notation, how is T evaluated to get a real number as 
the 
> result? Do  
> we model u as a column matrix and v as a row matrix?  Thanks for your 
time. AG  
> 
> 
> 
---------------------------------------------------------------------------- 

> 
> Dr Russell Standish Phone 0425 253119 (mobile) 
> Principal, High Performance Coders [email protected] 
> http://www.hpcoders.com.au 
> 
----------------------------------------------------------------------------

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