On Thursday, November 13, 2025 at 11:14:13 PM UTC-7 Russell Standish wrote:

On Sat, Nov 08, 2025 at 05:25:16AM -0800, Alan Grayson wrote: 
> In some treatments of tensors, they're described as linear maps. So, in 
GR, if 
> we have a linear map described as a 4x4 matrix of real numbers, which 
operates 
> on a 4-vector described as a column matrix with entries (ct, x, y, z), 
which 
> transforms to another 4-vector, what must be added in this description to 
claim 
> that the linear transformation satisfies the definition of a tensor? TY, 
AG 

The operation of matrix multiplication is linear over the vectors on 
the right hand side. 

Is that what you're missing?


*Suppose T is a tensor which operates on vector v in some vector space. 
Then T(v)*
*maps to a real number and is linear in v. If we change coordinates, v's 
coordinates will*
*change but v remains the same, so T is invariant wrt coordinate 
transformations.*
*Now let's look at the situation using matrix representation and assume 
we're dealing*
*with a 4 dimensional spacetime manifold. Then T can be represented by a 
4x4 matrix,*
*and v can be represented as a column matrix with entries ct, x, y, z.  
When T operates *
*on v, we get another column vector, and not a real constant! What am I 
doing wrong? *
*Doesn't every tensor map to a real number? Also, if T is a function of two 
vectors, **T(u,v),*
*then using matrix notation, how is T evaluated to get a real number as the 
result? **Do *
*we model u as a column matrix and v as a row matrix?  Thanks for your 
time. AG* 


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Dr Russell Standish Phone 0425 253119 (mobile) 
Principal, High Performance Coders [email protected] 
http://www.hpcoders.com.au 
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