Bruno Marchal skrev: > > To sum up; finite ordinal and finite cardinal coincide. Concerning > infinite "number" there are much ordinals than cardinals. In between > two different infinite cardinal, there will be an infinity of ordinal. > We have already seen that omega, omega+1, ... omega+omega, > omega+omega+1, ....3.omega, ... 4.omega .... ....omega.omega ..... > omega.omega.omega, .....omega^omega ..... are all different ordinals, > but all have the same cardinality. > Was it not an error there? 2^omega is just the number of all subsets of omega, and the number of all subsets always have bigger cardinality than the set. So omega^omega can not have the same cardinality as omega.

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