On Thu, Aug 20, 2009 at 12:32 PM, Bruno Marchal<marc...@ulb.ac.be> wrote:
> Hi,
> I give the solution of the first of the last exercises.
> This motivates the definition of the following function from N to N,
> called factorial.
> factorial(0) = 1, and factorial(n) = n*(n-1)*(n-2)*(n-3) * ... *1, if
> is n is different from 0.
> Note this: if n is different from 0, for each n we have that fact(n) =
> n*fact(n).

Of course you meant fact(n)=n*fact(n-1).


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