On 2/1/2014 9:46 AM, John Clark wrote:
On Sat, Feb 1, 2014 at 7:57 AM, Edgar L. Owen <edgaro...@att.net
<mailto:edgaro...@att.net>> wrote:
> One might think it was the acceleration that slowed time on A's clock,
BUT the
point is that A's acceleration was only 1g throughout the entire trip which
was
exactly EQUAL to B's gravitational acceleration back on earth. So if the
accelerations were exactly equal during the entire trip how could A's
acceleration
slow time but B's not slow time by the same amount?
If A were going into space and accelerating upward off the surface of the Earth at one g
(32 feet per second per second), then he would be experiencing 2g, one g from the Earth
and one g from his continuing change in upward velocity.
But A would experience acceleration quickly decreasing to 1g as he left the vicinity of
the Earth. And the result wouldn't change if B entered a centrifuge and experienced an
exactly equal acceleration while remaining on Earth. This is why I emphasize that it is
NOT an effect of acceleration, it is a geometric effect of different path lengths.
Brent
> both = 1g throughout the entire trip
No, not during the entire trip. And if the space traveler ever wants to return to Earth
to rejoin his friend so they can directly compare their clocks then he's going to have
to change the direction of his acceleration by 180 degrees. So their clocks will not
match because their travel experiences were not symmetrical.
John K Clark
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