Jesse,

I gave you a clear easy to follow and understand procedure that I believe 
works in every case to determine if any two clock time labeled events 
occurred in the same p-time moment or not.

I'm sorry if you don't see how it works. I don't see how I can make it much 
clearer. It's just applying standard relativity calculations. You don't 
have to do them backwards BTW. If you start with A and B in the same frame, 
they will automatically be in the same p-time present moment so you can do 
the math forward from there to establish the same p-times for all different 
clock time of A and B when one starts to travel. That's simple standard 
relativistic calculations.

I don't have time to start doing calculations for you but the procedures I 
gave you are standard relativistic calculations that should enable you to 
determine which clock time labeled events occurred at the same p-times if 
you want.

Edgar



On Saturday, February 8, 2014 5:28:08 PM UTC-5, jessem wrote:
>
>
>
>
> On Sat, Feb 8, 2014 at 4:01 PM, Edgar L. Owen <[email protected]<javascript:>
> > wrote:
>
> Jesse,
>
> Yes, I think there is always a way to determine if any two events happen 
> at the same point in p-time or not, provided you know everything about 
> their relativistic conditions.
>
> You do this by essentially computing their relativistic cases BACKWARDS to 
> determine which point in each of their worldlines occurred at the same 
> p-time.
>
> Take 2 observers, A and B.
>
> 1. If there is no relative motion or gravitational/acceleration 
> differences you know that every point t in A's CLOCK time was in the same 
> present moment as every point t' in B's CLOCK TIME when t=t'.
>
>
> And what if there *are* gravitational differences, if there are sources of 
> gravity nearby and they are at different points in space? Gravity is dealt 
> with using general relativity, and in general relativity there is no 
> coordinate-indepedent way to define the "relative motion" of observers at 
> different points in space (see discussion at 
> http://math.ucr.edu/home/baez/einstein/node2.html for details). And the 
> only coordinate-independent definition of "acceleration" is proper 
> acceleration (what an observer would measure with an accelerometer that 
> shows the G-forces they are experiencing), but all observers in freefall 
> have zero proper acceleration, so if you think there is a 
> "gravitational/acceleration difference" between an observer orbiting far 
> from a black hole and one falling towards it close to the event horizon, 
> you can't quantify it using proper time.
>
>  
>
>
> 3. In the case of twins DURING the trip in relative motion we can always 
> back calculate the relativistic effects to make a statement of the form 
> "the twins were in the same current moment of p-time when A read his own 
> clock as A-t and B's clock as B-t, AND B read his own clock as B-t' and 
> read A's clock as A-t'. In this case A-t will NOT = A-t', and B-t will NOT 
> = B-t', but they will have specific back calculable t values for every 
> current p-time during the trip. Thus if we have all the details of that 
> trip's motion we should always be able to back calculate to determine which 
> clock times of any two observers occurred in the same current p-time 
> SIMULTANEITY even when those observers cannot agree on CLOCK time 
> simultaneity among themselves.
>
>
> HOW would you "back calculate" it though? Even if we set aside my 
> questions about gravity above and just look at a case involving flat SR 
> spacetime, your answer gives no details. If you have any procedure in mind, 
> could you apply it to a simple example? Let's say Alice is sent on a ship 
> that moves away from Bob on Earth on the day they are both born, and the 
> ship moves with speed of 0.8c relative to the Earth, towards a planet 12 
> light-years away in the Earth's frame. Alice arrives at that planet when 
> she is 9 years old, and at that point the ship immediately turns around and 
> heads back towards Earth with a relative speed of 0.6c. Alice experiences 
> the return journey to take 16 more years, so when she returns to Earth she 
> is 25 years old, but Bob is 35 years old when they meet. Can you show me 
> how to back-calculate how old Bob was when he was in the same moment of 
> p-time as Alice turning 9 and her ship reaching the planet and turning 
> around?
>  
>
>
> So since p-time has no metric itself you can't just compare p-time t 
> values because there are none. You have to back calculate clock times to 
> determine in what current p-times they occurred.
>
> So that's how we determine whether any two events occurred a the same 
> p-times or not. You should always be able to determine that even though you 
> can assign a p-time t value because there are none because p-time doesn't 
> have a metric.
>
>
> I have never asked you for a p-time "value", I'm only interested in the 
> question of which events are simultaneous in p-time. I don't think your 
> answers so far have made it clear that you have any well-defined procedure 
> for determining this, see my questions above.
>
> Jesse
>
>  
>
>
> Edgar
>
>
>
> On Friday, February 7, 2014 12:51:32 PM UTC-5, jessem wrote:
>
>
>
>
> On Fri, Feb 7, 2014 at 12:27 PM, Edgar L. Owen <[email protected]> wrote:
>
> Jesse,
>
> Well you just avoid most of my points and logic.
>
>
> Can you itemize the specific points you think I'm avoiding?
>  
>
>
> But yes, I agree with your operational definition analysis. That is 
> EXACTLY my point. That what our agreed operational definitions define is a 
> COMMON PRESENT MOMENT, and NOT a same point in spacetime, because the logic 
> of it does not support it being in the same point in space, only in the 
> same point of time
>
>
> Huh? Even if one accepts p-time, that "operational definition" still must 
> be seen as a merely *approximate* way of defining the same point of p-time, 
> not exact, just like with "same point in space" or "same point in 
> spacetime". If I bounce some light off you, surely you agree that the event 
> of it reflecting off you occurred at a slightly earlier point in p-time 
> that the event of reaching my eyes (or instruments)? Likewise if I feel our 
> palms meet in a handshake, I don't actually begin to feel it until a 
> slightly later moment of p-time than the moment our palms first made 
> physical contact, and likewise for any shift or movement you might make 
> with your hands. If you want to talk in a non-approximate way, all our 
> experiences are slightly delayed impressions of events that occured in the 
> past, regardless of whether we're talking about p-time or coordinate time.
>
> On this subject, could you address the question I asked in another post 
> about whether you think there's any empirical way to determine whether two 
> events in the past occurred at the same p-time, or whether the assumption 
> of p-time simultaneity is a purely metaphysical one and that there's no way 
> of knowing whether a specific pair of events we have records of actually 
> happened simultaneously in p-time?
>
>  
>
> and that same point in time is obviously not anything that relativity 
> predicts, because no matter what set of coordinates you choose, relativity 
> always gives 2 different real answers for the ages of the twins. 
>
>
>
> I don't know what part of this you're not understanding, "same point in 
> time" in relativity just MEANS that two events are assigned the same time 
> coordinate, relativity doesn't deal with any absolute notion of 
> simultaneity of distant events whatsoever. And relativity definitely does 
> predict situations where clocks show different readings at the same 
> coordinate time--do you deny this?
>
> Like I said earlier, there is a direct spatial analogy here that makes 
> perfect sense if you don't assume p-time from the start. If two different 
> measuring tapes cross, and the point where they cross is at the 30 cm mark 
> on one tape and the 40 cm mark on the other, and there's a Cartesian 
> coordinate grid on the surface under them which says this point has an 
> x-coordinate of 50, wouldn't you say that the measuring tapes DO cross at 
> the "same point in space"? Would the fact that the tapes themselves show 
> two different readings at that point negate this?
>
> As for your last paragraph you seem to agree that both our operational 
> definitions DO support the notion of a same present moment, just not that 
> time flows.
>
>
> How do you figure? My last paragraph was just clarifying what I meant by 
> arguments "dependent on conscious experience" vs. arguments defined in 
> terms of straightforward experiments whose results we can all observe and 
> agree on. Nowhere did I say anything in support of an absolute "same 
> present moment". 
>
>
> Jesse
>
>
>
> On Friday, February 7, 2014 8:49:32 AM UTC-5, jessem wrote:
>
>
> On Fri, Feb 7, 2014 at 7:57 AM, Edgar L. Owen <[email protected]> wrote:
>
> Jesse,
>
> OK, here's the detailed analysis of how I see the current state of this 
> issue that I promised:
>
>
> A few points:
>
> 1. Since you asked let me repeat my 'operational definition' of the 
> present moment that I used before. The twins meet, shake hands and compare 
> watches. That is the operation definition.
>
> That is essentially the same as your reflected light operational 
> definition with which I have no problem.
>
> 2. However it is important to note that that works not just for the twins 
> together, but for every single twin by himself. Because any twin or 
> observer can shake his own hand, look at his own watch, or note that the 
> light reflected from a mirror in his hand takes minimal time to return.
>
> Therefore what is true for the twins together is also true for each twin 
> separately, and is true for every observer in the universe as well. <
>
> ...

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