>> I'm not reading Max's book, so I don't know exactly what he said,

Im reading the quote Jason kindly provided and responding to exactly what 
Tegmark said.

>>but using FPI as in Everett QM and writing down which of two equally likely 
>>events you actually experience is an example of bernoulli trials.  

and the figures I've been stating reflect bernoulli trials precisely.

>> The proportion of 1s and 0s both converge to 1/2 in probability. 

but in doing so call in to question definitions of 'about' 'roughly' and 
'almost all'. But then you haven't read the Tegmark quote so you won't be able 
to add anything substantive about that.

>> It is irrelevant that the proportion of subsequences that have exactly 
>> equally 1s and 0s goes down.

Whats irrelevant is the use of proportion of 1s and 0s in determining 'apparent 
randomness'. It doesn't. Which is my point. The figures for exact proportions 
were just my arse about tit way of getting there.

But still, even though I seemed to get there on my tod, at least I know what a 
Bernoulli trial is now. Thanks for that.

Date: Mon, 3 Mar 2014 21:43:29 -0800
From: [email protected]
To: [email protected]
Subject: Re: Tegmark and UDA step 3


  
    
  
  
    I'm not reading Max's book, so I don't
      know exactly what he said, but using FPI as in Everett QM and
      writing down which of two equally likely events you actually
      experience is an example of bernoulli trials.  The proportion of
      1s and 0s both converge to 1/2 in probability.  This is exactly
      the way prediction of probabilities are evaluated experimentally. 
      It is irrelevant that the proportion of subsequences that have
      exactly equally 1s and 0s goes down.

      

      Brent

      

      On 3/3/2014 8:32 PM, chris peck wrote:

    
    Hi Liz

      

      >> I'm not sure I follow.

      

      Me neither.

      

      >>  wrote down your room number each time, you'd in
        almost all cases find that the sequence of zeros and ones you'd
        written looked random, with zeros occurring about 50% of the
        time."

      

      there would be no 'about' it were your interpretation right, Liz.
      

      

      It would be all the time, exactly 50%. 

      

      Hes saying that zeros occur about 50%of the time in the zeros and
      ones you have written down. 

      

      That corresponds to the individual bit strings. Not the entire
      collection of them.

      

      >> I guess the sloppy phrasing is he implies 0s happen
        half the time in most sequences?

      

      I suspect its sloppy interpretation rather than sloppy phrasing
      that implies that. 

      

      >> I don't know if that is true (it's true for 6 of the
        16 sequences above)

      

      6/16 isn't half is it? I measured 1 divided by 2 just now and it
      still seems to come out as 0.5 here.

      

      >> or if it becomes more true (or almost true) with
        longer sequences. Maybe a mathematician can enlighten me?

      

      I wrote a little program Liz that collects together all the bit
      strings that can be made from 16 bits. Then it counts the number
      of 1s and 0s in each one. It has a little counter that goes up by
      one every time there are 8 zeros.

      

      there are 65536 combinations. 12870 of them have 8 zeros. 12870 /
      65536 * 100 = 19%.

      

      6/16*100 = 37%

      

      I don't know about you but 19, being less than 37, suggests to me
      that the percentage is going down. But ofcourse ask a
      mathematician if you're not certain of that yourself.

      

        >> I admit Max seems a little slapdash in how he phrases
        things in the chapters I've read so far, presumably because he's
        trying to make his subject matter seem more accessible.

      

      Yeah, which is preferable to people with similar ideas being slap
      dash in order to make them less accessible.
    

  





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