On Mon, Dec 31, 2018 at 2:46 PM Brent Meeker <[email protected]> wrote:

>
> *But you do know that the straightest path between events in Minkowski
> spacetime *
>

You do know don't you that Minkowski space is non-Euclidean because it
treats time differently than the other 3 dimensions but it is not curved so
it is useful in Special Relativity but not in General Relativity or
anything involving gravity.

*> is the longest duration path don't you.  *


And I hope you know the path yielding the longest proper time duration is
not the same as having the longest distance through spacetime as time is
just one dimension and spacetime involves 4. If r is the distance in space
and c the speed of light then the square of the distance in spacetime
between two events is  r^2-(ct)^2, so the largest possible t (proper time)
will give smallest possible distance through spacetime.


> > The Google definition seems not to consider mixed signature metrics.


Google said a geodesic is the shortest distance between 2 points on a
curves surface, time is just one dimension and you can't have a curved
surface with just one dimension.


> > in Minkowski space there is only one time-like geodesic that connects
> any given pair of time-like separated events,


True but curved spacetime is not Minkowski space and you can have more than
one one time-like geodesic connecting them.


> * > Even a twin paradox can be constructed this way by having the
> traveling twin's velocity reversed by the gravity of massive body far from
> the stay-home twin; which in GR is not a force.*
>

Then one twin would encounter a intense gravitational field that the other
twin did not and gravity will slow down a clock just like moving fast will.

> *What "Feynman's example"?*


I posted it a few days ago. it comes from "Surely you're joking Mr.
Feynman" he posed this puzzle to an assistant of Einstein:

"Y*ou blast off in a rocket which has a clock on board, and there's
a clock on the ground. The idea is that you have to be back when
the clock on the ground says one hour has passed. Now you want it so
that **when
you come back, your clock is as far ahead as possible. According to
Einstein, if you go very high, your clock will go faster, because the
higher something is in a gravitational field, the faster its clock goes.
But if you try to go too high, since you've only got an hour, you have to
go so fast to get there that the speed slows your clock down. So you can't
go too high. The question is, exactly what program of speed and height
should you make so that you get the maximum time on your clock?"*

*"This assistant of Einstein worked on it for quite a bit before he
realized that the answer is the real motion of matter. If you shoot
something up in a normal way, so that the time it takes the shell to go up
and come down is an hour, that's the correct motion. It's the fundamental
principle of Einstein's gravity--that is, what's called the "proper time"
is at a maximum for the actual curve."*

John K Clark

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