On Thu, Jan 3, 2019 at 3:58 AM Bruce Kellett <[email protected]> wrote:
> *> The 't' in your formula above is the coordinate time, not the proper > time. * > What the hell are you talking about? If I travel from event A to event B and use the formula x^2 + y^2 + z^2 -(ct)^2 where x,y,and z are the differences in spatial coordinates I observe and *t is the proper time* it took for me to make the trip I will get an invariant. If you also travel between event A and B but use a different path you will get entirely different numbers for x, y and z and you will get a different number for *the proper time t,* but when you plug in your numbers into x^2 + y^2 + z^2 -(ct)^2 you will get the exact same value I do. > *> The proper time is defined as the time kept by a perfect clock > travelling on a geodesic.* > No it is not! The proper time is defined as the time measured by a clock along ANY line through spacetime and it doesn't matter a hoot in hell if that line is a geodesic or not. And you said "*Proper time is the distance through spacetime*" but every book on physics on the planet will tell you that the distance through spacetime is an invariant; but proper time is NOT a invariant, different observers can have different proper times, even you know this because you said "*two different orbits of the Earth, both geodesics, can coincide at a pair of events. They will measure different proper times between those events*". So your ideas are not self consistent but then they had to be, spacetime distance and proper time aren't even in the same units. The reason you need both a odometer and a clock in your car is that they measure different things. And no matter how hard you try you're never going to be able to subtract seconds from meters, so why are we still arguing about this when it's obvious you're wrong? > > *And a geodesic is the path along which the rate of time is constant.* > What the hell?! Obviously the rate of time is always constant for any observer in the same reference frame as the clock regardless if the path is a geodesic or not, it will always change at the rate of one second per second . It doesn't take a Einstein to know that. John K Clark -- You received this message because you are subscribed to the Google Groups "Everything List" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To post to this group, send email to [email protected]. Visit this group at https://groups.google.com/group/everything-list. For more options, visit https://groups.google.com/d/optout.
