On Thursday, November 7, 2019 at 11:41:11 AM UTC-7, Brent wrote:
>
>
> On 11/6/2019 10:31 PM, Alan Grayson wrote:
>
> On Wednesday, November 6, 2019 at 11:20:23 PM UTC-7, Brent wrote:
>>
>>
>> On 11/6/2019 9:00 PM, Alan Grayson wrote:
>>
>>
>> On Wednesday, November 6, 2019 at 7:17:21 PM UTC-7, Brent wrote: 
>>>
>>>
>>>
>>> On 11/6/2019 4:44 PM, Alan Grayson wrote:
>>>
>>>
>>>
>>> On Wednesday, November 6, 2019 at 3:46:54 PM UTC-7, Brent wrote: 
>>>>
>>>>
>>>>
>>>> On 11/6/2019 12:05 AM, Alan Grayson wrote:
>>>>
>>>>
>>>>
>>>> On Tuesday, November 5, 2019 at 10:23:58 PM UTC-7, Brent wrote: 
>>>>>
>>>>>
>>>>>
>>>>> On 11/5/2019 9:09 PM, Alan Grayson wrote:
>>>>>
>>>>> Crossing the horizon is a nonevent for the most part. If you try to 
>>>>>> accelerate so you hover just above it the time dilation and that you are 
>>>>>> in 
>>>>>> an extreme Rindler wedge will mean you are subjected to a torrent of 
>>>>>> radiation. In principle a probe could accelerate to 10^{53}m/s^2 and 
>>>>>> hover 
>>>>>> a Planck unit distance above the horizon. You would be at the stretched 
>>>>>> horizon. This would be almost a sort of singular event. On the other 
>>>>>> hand 
>>>>>> if you fall on an inertial frame inwards there is nothing unusual at the 
>>>>>> horizon.
>>>>>>
>>>>>> LC
>>>>>>
>>>>>
>>>>> Do you mean that clock rates continue to slow as an observer 
>>>>> approaches the event horizon; then the clock stops when crossing, or on 
>>>>> the 
>>>>> event horizon; and after crossing the clock resumes its forward rate? AG 
>>>>>
>>>>>
>>>>> He means the infalling clock doesn't slow down at all.   Whenever you 
>>>>> see the word "clock" in a discussion of relativity it refers to an *ideal 
>>>>> clock*.  It runs perfectly and never speeds up or slows down.  It's 
>>>>> called *relativity* theory because observers *moving relative* to the 
>>>>> clock *measure it* to run slower or faster than their (ideal) clock.
>>>>>
>>>>> Brent
>>>>>
>>>>
>>>> I see. So if for the infalling observer, his clock seems to be running 
>>>> "normally", but for some stationary observer, say above the event horizon, 
>>>> the infalling clock appears to running progressively slower as it falls 
>>>> below the EH, even if it can't be observed or measured. According to GR, 
>>>> is 
>>>> there any depth below the event horizon where the infalling clock 
>>>> theoretically stops? 
>>>>
>>>>
>>>> I just explained that *clocks never slow* in relativity examples.  So 
>>>> now you ask if there's a place they stop??
>>>>
>>>> Brent
>>>>
>>>
>>> I know, but that's not what I asked. Again, the infalling clock is 
>>> measured as running slower than a stationary clock above the EH. As the 
>>> infalling clock goes deeper into the BH, won't its theoretical rate 
>>> continue to decrease as compared to the reference clock above the EH? How 
>>> slow can it get? AG 
>>>
>>>
>>> It *appears* (if the observer at infinity could see the extreme red 
>>> shift) to *asymptotically approach stopped *as it approaches the event 
>>> horizon.  This is because the photons take longer and longer to climb out 
>>> because they have to traverse more and more spacetime.
>>>
>>> Brent
>>>
>>
>> I'm referring to two clocks; one at finite distance above the EH, and 
>> other infalling. Doesn't the infalling clock seem to run progressively 
>> slower from the POV of the other clock, as it falls lower and lower? AG 
>>
>> I appears to run slower as seen by the distant observer.
>>
>> Brent
>>
>
> As it goes deeper and deeper into the BH, does the clock ever appear to 
> STOP? AG
>
>
> It doesn't appear at all when it passes the event horizon.  It appears to 
> stop as it approaches the event horizon.
>
> Brent
>

I know it can't be observed as it falls through the EH. That's why I 
referred to clock "readings" after falling through as "theoretical". On the 
other hand, LC says falling through the EH is a non-event, as if the 
infalling clock behaves as we expect based on a clock entering a region of 
strong gravitational field. But let's say the clock appears to stop as it 
approaches the EH, which is what I thought. How do you reconcile this 
prediction, which is certainly weird? AG 

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