On 4/26/2020 6:37 PM, Alan Grayson wrote:


On Sunday, April 26, 2020 at 6:39:15 PM UTC-6, Brent wrote:



    On 4/26/2020 3:22 PM, Alan Grayson wrote:


    On Sunday, April 26, 2020 at 1:46:59 PM UTC-6, Brent wrote:



        On 4/26/2020 9:24 AM, Alan Grayson wrote:


        On Sunday, April 26, 2020 at 9:48:45 AM UTC-6, John Clark
        wrote:

            On Sat, Apr 25, 2020 at 12:49 PM Alan Grayson
            <[email protected]> wrote:

                /> How does QM tell us that conservation of energy
                can be violated for brief durations? If you apply
                the time-energy form of the UP for your proof,
                please state the context of your proof, that is,
                exactly what do E and t stand for./


            The shorter the time (t) a system is under observation
            the larger the amount of energy (E) could pop into
            existence from nothing without direct detection, enough
            energy to create virtual particles. And you can
            calculate how large the indirect effects these virtual
            particles would have on the system.


        As I understand the UP, it's a statistical statement about
        an ensemble of observations, say for position and momentum
        of identical particles. It says nothing about the result of
        events, say for the position and momentum of a single
        particle or event. Doing some arithmetic to get the
        time-energy form of the UP does not change this reality. As
        a result, your description of what happens to a single
        particle, virtual or not, is not intelligible. Please try
        again. AG

        The UP doesn't apply to virtual particles because it refers
        to the result of conjugate measurement (projection)
        operators.  You can't measure virtual particles.

        Brent


    In its usual form, does the UP allow us to measure position and
    momentum *simultaneously*, or must we measure each variable
    independently (for an ensemble of identical particles, of
    course)? What is proper interpretation of the time/energy form of
    the principle in statistical terms? TIA, AG

    You can measure them simultaneously; but when you repeat the pair
    of measurements on many identically prepared particles you find
    that there is a scatter in the position  and a scatter in the
    momentum such that the HUP is satisfied.

    Brent


Can you give an example of the ensembles used in applying the time-energy form of the UP? TIA, AG

https://arxiv.org/pdf/quant-ph/0511245.pdf

There's also an interesting discussion of how to measure time in QM.  Since time is not an operator you have to construct a clock which defines the physical meaning of time. http://www.god-does-not-play-dice.net/clock_peres.pdf

Brent

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