On Sunday, April 26, 2020 at 1:46:59 PM UTC-6, Brent wrote:
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>
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> On 4/26/2020 9:24 AM, Alan Grayson wrote:
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> On Sunday, April 26, 2020 at 9:48:45 AM UTC-6, John Clark wrote: 
>>
>> On Sat, Apr 25, 2020 at 12:49 PM Alan Grayson <[email protected]> 
>> wrote:
>>
>> *> How does QM tell us that conservation of energy can be violated for 
>>> brief durations? If you apply the time-energy form of the UP for your 
>>> proof, please state the context of your proof, that is, exactly what do E 
>>> and t stand for.*
>>
>>
>> The shorter the time (t) a system is under observation the larger the 
>> amount of energy (E) could pop into existence from nothing without direct 
>> detection, enough energy to create virtual particles. And you can calculate 
>> how large the indirect effects these virtual particles would have on the 
>> system.
>>
>
> As I understand the UP, it's a statistical statement about an ensemble of 
> observations, say for position and momentum of identical particles. It says 
> nothing about the result of events, say for the position and momentum of a 
> single particle or event. Doing some arithmetic to get the time-energy form 
> of the UP does not change this reality. As a result, your description of 
> what happens to a single particle, virtual or not, is not intelligible. 
> Please try again. AG 
>
>
> The UP doesn't apply to virtual particles because it refers to the result 
> of conjugate measurement (projection) operators.  You can't measure virtual 
> particles.
>
> Brent
>

In its usual form, does the UP allow us to measure position and momentum 
*simultaneously*, or must we measure each variable independently (for an 
ensemble of identical particles, of course)? What is proper interpretation 
of the time/energy form of the principle in statistical terms? TIA, AG 

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