On Thursday, July 23, 2020 at 8:56:03 PM UTC-6, Alan Grayson wrote:
>
>
>
> On Thursday, July 23, 2020 at 11:59:59 AM UTC-6, Brent wrote:
>>
>>
>>
>> On 7/23/2020 4:41 AM, Lawrence Crowell wrote:
>>
>> On Thursday, July 23, 2020 at 5:56:32 AM UTC-5 [email protected] wrote:
>>
>>>
>>>
>>> On Saturday, July 18, 2020 at 6:31:23 AM UTC-6, Alan Grayson wrote: 
>>>>
>>>>
>>>>
>>>> On Saturday, July 18, 2020 at 6:18:28 AM UTC-6, Lawrence Crowell wrote: 
>>>>>
>>>>> The tortoise coordinates is found from the Schwarzschild metric 
>>>>>
>>>>> ds^2 = (1 - 2m/r)dt^2 -  (1 - 2m/r)^{-1}dr^2 - r^2dΩ^2   
>>>>>
>>>>> where for a signal leaving a point near the black hole with ds = 0 
>>>>> (null path) and propagating radially out, dΩ = 0, we have dt = dr/(1 - 
>>>>> 2m/r) which then leads to
>>>>>
>>>>> T = t - t0 - 2m ln|r - 2m|.
>>>>>
>>>>> That is the tortoise coordinate. Please look this up to read further. 
>>>>> I can't spend beaucoup time going over this for weeks to come.
>>>>>
>>>>> LC
>>>>>
>>>>
>>>> You don't have to. We're done.  But you should IMO address Brent's 
>>>> objection, maybe on another thread. AG
>>>>
>>>
>> I don't know what objection you're referring to.  LC is just showing why 
>> it takes a distant observer forever to see an infalling object reach the 
>> event horizon of a black hole.
>>
>> Brent
>>
>
> Your words: 
>
> I wonder about the use of cicumlocutions like "from the perspective of an 
> outside observer".  In special relativity it it is often said that a moving 
> object will looked shortened along the direction of motion.  But as Terrell 
> pointed out that's not at all how they look.  It is more accurate to say 
> that *measuring* a moving a object will show that it is shortened along 
> the direction of motion; the difference being that the measurement corrects 
> for the fact that you want the difference in arrival time of photons that 
> left the ends of the object at the same time (an ill defined concept), 
> instead of the image formed by photons that arrived at the same time.  But 
> then I think, why not correct for the Lorentz contraction too in the 
> measurement and arrive at what we might call "the proper length".  That's 
> just as "measured" as either of the other two.
>
> By the same reasoning, you're really saying the visual impression of a 
> distant observer is that infalling stuff appears to be on the surface of 
> the event horizon. Which is because it takes forever for photons to reach 
> him.  But why should he be so naive.  He knows what he's seeing is 
> arbitrarily far in his past; so what he should be said to "measure" or 
> "calculate" is that the stuff has already been annihilated at the 
> "singularity" in his reference frame.
>
> -----------------------------------------------------
>
> I forget why LC brought up this particular coordinate system. He had some 
> point in response to a comment I made. I'll have to review my comments; 
> maybe that the gravitational field due to a BH, external to the event 
> horizon, has an objective reality. AG
>

I just reviewed LC's comments. He was claiming that tortoise coordinates 
show the existence of the gravitational field due to a BH, external to it. 
He wasn't limiting his argument, which you apparently objected to, to how 
long a distant observer would have to view an infalling mass, to see it 
disappear. AG 

>
>  
>
>>
>>
>>> When it comes to GR, you're a genius; no question about it. I wouldn't 
>>> want to waste your valuable time. But consider this; the Schwartzschild 
>>> metric applies to NON-ROTATING masses. Do you really think a massive 
>>> contracting star which forms a BH will be non-rotating? Obviously, it will 
>>> be RAPIDLY rotating, like an ice skater who contracts her arms. Brent also 
>>> had some substantive questions about your model. But I see you prefer your 
>>> illusions than to address his objections. AG
>>>
>>
>> The result is similar, but more complex. The same calculation can be done 
>> for the Kerr solution. It is just a lot more complicated mathematically.
>>
>> LC
>>  
>> -- 
>> You received this message because you are subscribed to the Google Groups 
>> "Everything List" group.
>> To unsubscribe from this group and stop receiving emails from it, send an 
>> email to [email protected].
>> To view this discussion on the web visit 
>> https://groups.google.com/d/msgid/everything-list/5b3752f7-55da-4c90-bc8b-11e1b8f42344n%40googlegroups.com
>>  
>> <https://groups.google.com/d/msgid/everything-list/5b3752f7-55da-4c90-bc8b-11e1b8f42344n%40googlegroups.com?utm_medium=email&utm_source=footer>
>> .
>>
>>
>>

-- 
You received this message because you are subscribed to the Google Groups 
"Everything List" group.
To unsubscribe from this group and stop receiving emails from it, send an email 
to [email protected].
To view this discussion on the web visit 
https://groups.google.com/d/msgid/everything-list/28206371-de23-4dfd-9e2b-978ad5dbcec2o%40googlegroups.com.

Reply via email to