The tortoise coordinates is found from the Schwarzschild metric

ds^2 = (1 - 2m/r)dt^2 -  (1 - 2m/r)^{-1}dr^2 - r^2dΩ^2   

where for a signal leaving a point near the black hole with ds = 0 (null 
path) and propagating radially out, dΩ = 0, we have dt = dr/(1 - 2m/r) 
which then leads to

T = t - t0 - 2m ln|r - 2m|.

That is the tortoise coordinate. Please look this up to read further. I 
can't spend beaucoup time going over this for weeks to come.

LC

On Friday, July 17, 2020 at 11:08:00 PM UTC-5 [email protected] wrote:

>
>
> On Friday, July 17, 2020 at 11:54:20 AM UTC-6, Lawrence Crowell wrote:
>>
>> On Friday, July 17, 2020 at 11:43:48 AM UTC-5 [email protected] wrote:
>>
>>>
>>>
>>> On Friday, July 17, 2020 at 5:34:17 AM UTC-6, Alan Grayson wrote:
>>>>
>>>>
>>>>
>>>> On Friday, July 17, 2020 at 4:48:51 AM UTC-6, Lawrence Crowell wrote:
>>>>>
>>>>> On Friday, July 17, 2020 at 5:01:41 AM UTC-5 [email protected] 
>>>>> wrote:
>>>>>
>>>>>>
>>>>>>
>>>>>> On Thursday, July 16, 2020 at 7:50:07 PM UTC-6, Alan Grayson wrote:
>>>>>>>
>>>>>>>
>>>>>>>
>>>>>>> On Thursday, July 16, 2020 at 5:08:57 PM UTC-6, Lawrence Crowell 
>>>>>>> wrote:
>>>>>>>>
>>>>>>>> Gravitons do not escape from a BH, any more than can light. 
>>>>>>>> However, from the perspective of an outside observer all matter than 
>>>>>>>> went 
>>>>>>>> into a BH is on the surface above the event horizon, called the 
>>>>>>>> stretched 
>>>>>>>> horizon. 
>>>>>>>>
>>>>>>>> LC
>>>>>>>>
>>>>>>>
>>>>>>> Gravitons might not exist (and hence quantum gravity can't exist)  
>>>>>>> But whatever the case, how can BH's interact gravitationally with 
>>>>>>> objects 
>>>>>>> beyond its event horizon? You say this doesn't happen. I don't 
>>>>>>> understand 
>>>>>>> your argument. AG 
>>>>>>>
>>>>>>
>>>>> That you are saying this illustrates you do not understand general 
>>>>> relativity.
>>>>>  
>>>>>
>>>>>>
>>>>>> I may have identified the thousand pound gorilla in the room; the 
>>>>>> hypothetical force carrying particle of the quantum gravitating field, 
>>>>>> the 
>>>>>> graviton, which for BH's doesn't exert any force! AG 
>>>>>>
>>>>>
>>>>> I have no idea why you are saying this. Gravitation is not a force in 
>>>>> the usual sense and so the graviton does not produce a force in the 
>>>>> standard meaning. For the weak field limit the nonlinear terms are 
>>>>> negligable and a gravitational wave is linear. This is easily quantized. 
>>>>> In 
>>>>> fact it is similar to the Hanbury-Brown and Twiss theory of the diphoton. 
>>>>> It is when the field becomes strong that general relativity becomes 
>>>>> nonlinear and runs into trouble with quantum mechanics.
>>>>>
>>>>> LC
>>>>>
>>>>
>>>> I assumed a quantum field theory of gravity must have a particle 
>>>> associated with it, and that this particle is called the graviton. Gravity 
>>>> is a fictitious force. So what would the role of the graviton be, if not 
>>>> to 
>>>> produce some force? If you detect gravitational waves, don't they consist 
>>>> of gravitons if a quantum theory of gravity exists, analogous to photons 
>>>> in 
>>>> EM waves? AG
>>>>
>>>
>>> Before you can present yourself as deeply knowledgeable of GR, you 
>>> should be able to give a coherent account how presumably *isolated* 
>>> bodies such as BH's, can gravitationally interact with what's exterior to 
>>> them. If gravitons can't do that in the context of a quantum theory of 
>>> gravity, what can?  AG
>>>
>>
>> It is the delay or tortoise coordinate basis for an external observer.
>>
>
> This is a tough subject to wrap one's head around. Wiki has a decent 
> article on it. There's an objective gravitational effect of a BH beyond its 
> event horizon. Are you claiming that the effect is only supported by theory 
> by a particular choice of coordinate system for an external observer? AG 
>
>>
>> LC 
>>
>

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