One needs to define the observer + measurement apparatus. In conventional QM one associates to a measurement device made ready to measure some property of a system a Hermitian operator. But if we pursue the MWI rigorously, then one should associate a set of commuting operators to a conscious experience of an observer. And this should then follow from a description of consciousness as the computational state of some algorithm.

So, at this very moment my experience while I'm typing these words must be the result of a particular algorithm that is processing a particular set of data. I cannot in principle see the difference of that exact algorithm being implemented in different parts of the multiverse. At least not at that very moment when that particular set of data is processed.

An algorithm can be described by a time evolution operator U that acts on an input state and maps it to the state one computational step later. The preferred basis then arises from selecting the sectors where the algorithm representing the observer exists. The algorithm will have some valid input states |input> and corresponding output states |output(in)> = U|input>, we can then write:

U = sum over all |input>, |output> of |output><output|U|input><input| = sum over all |input> of |output(input)><input|



Suppose that we seek the observer represented by the operator U who has some definite experience. Whatever the observer is experiencing will be some course grained description of the precise inputs the actual data that U could be processing. So, we then consider limiting the summation above to only those input states that correspond to the specified coarse grained description. So, one can say that we need to narrow down U to some definite experience, but we then still end up summing over a very large set of states, because a particular conscious experience does not correspond to a definite physical state.

A simple example is to consider simulating a spin measurement using a quantum computer. The spin is then represent by a qbuit and the "observer" measuring the spin would then be the CNOT operator that takes the qubit representing the spin as the control qubit while the other qubit that it acts on is initialized to be |0>. So, one can then say that there exists a "CNOT observer". This definition is then well defined w.r.t. changing the basis.

Saibal



On 20-12-2021 18:01, Jesse Mazer wrote:
When you say the MWI + Born rule "yields an unambiguous framework for
a fundamental theory" are you assuming the idea of probability being
equal to amplitude squared only applies to "measurements", or that it
would somehow apply at all times in the MWI? If the former there would
seem to be some ambiguity about what a "measurement" is; if the
latter, I believe MWI advocates still don't have an agreed-upon answer
to the "preferred basis problem" discussed at
https://physics.stackexchange.com/questions/65177/is-the-preferred-basis-problem-solved

On Mon, Dec 20, 2021 at 4:03 AM smitra <[email protected]> wrote:

On 20-12-2021 03:05, Bruce Kellett wrote:
On Mon, Dec 20, 2021 at 12:23 PM John Clark <[email protected]>
wrote:

On Sun, Dec 19, 2021 at 7:59 PM Brent Meeker
<[email protected]>
wrote:

On 12/19/2021 5:25 AM, John Clark wrote:
By contrast the Many Worlds Theory only makes one assumption,
Schrodinger's Equation means what it says. So Many Worlds wins.

_> It also makes the assumption that the eigenvalues of a
measurement are realized probabilistically._

What is the eigenvalue of a temperature of 72°F? It doesn't have
one.
A measurement doesn't have an eigenvalue but a matrix does, such
as
the one that describes the Schrodinger Wave. And no quantum
interpretation needs to assume there is a relationship between the
square of the absolute value of that wave and probability because
it
is observed to be true.

The Born Rule cannot be derived from the Schrodinger equation; it
has
to be added as a further independent assumption. So it is not true
that Many Worlds makes only one assumption. It requires just as
many
assumptions as collapse theories.

Bruce

Yes, but with those assumptions it yields an unambiguous framework
for a
fundamental theory. In case of collapse theories, you're stuck with
a
phenomenological theory that cannot be improved, because you are not

allowed to describe observers and observations within the collapse
frameworks. It's a bit like the difference between statistical
mechanics
and thermodynamics, if in the latter case textbooks were to insist
that
you are only allowed to consider certain types of heat engines that
operate in the quasistatic limit.

Saibal


If it were not true Schrodinger's Wave would be completely
useless
and there would be no reason any physicist would bother to
calculate
it.

--
You received this message because you are subscribed to the Google
Groups "Everything List" group.
To unsubscribe from this group and stop receiving emails from it,
send
an email to [email protected].
To view this discussion on the web visit


https://groups.google.com/d/msgid/everything-list/CAFxXSLTFdzA%3Dg9GTTiC2aLdJZ76tHYA3Bvxo2WrrvdnAXY-QQg%40mail.gmail.com
[1].


Links:
------
[1]


https://groups.google.com/d/msgid/everything-list/CAFxXSLTFdzA%3Dg9GTTiC2aLdJZ76tHYA3Bvxo2WrrvdnAXY-QQg%40mail.gmail.com?utm_medium=email&utm_source=footer

--
You received this message because you are subscribed to the Google
Groups "Everything List" group.
To unsubscribe from this group and stop receiving emails from it,
send an email to [email protected].
To view this discussion on the web visit

https://groups.google.com/d/msgid/everything-list/8cffa6afc016a115e5fa8bd104135059%40zonnet.nl.

 --
You received this message because you are subscribed to the Google
Groups "Everything List" group.
To unsubscribe from this group and stop receiving emails from it, send
an email to [email protected].
To view this discussion on the web visit
https://groups.google.com/d/msgid/everything-list/CAPCWU3JOTt6Msg%3DXiGTpoEK8TNq3mqqWtSi-s9xgA4OPpQGRjw%40mail.gmail.com
[1].


Links:
------
[1]
https://groups.google.com/d/msgid/everything-list/CAPCWU3JOTt6Msg%3DXiGTpoEK8TNq3mqqWtSi-s9xgA4OPpQGRjw%40mail.gmail.com?utm_medium=email&utm_source=footer

--
You received this message because you are subscribed to the Google Groups 
"Everything List" group.
To unsubscribe from this group and stop receiving emails from it, send an email 
to [email protected].
To view this discussion on the web visit 
https://groups.google.com/d/msgid/everything-list/53c25e75a284b135d3a47efb955c44f0%40zonnet.nl.

Reply via email to