On Thursday, December 19, 2024 at 1:21:05 AM UTC-7 Jesse Mazer wrote:

On Thu, Dec 19, 2024 at 1:05 AM Alan Grayson <[email protected]> wrote:

On Wednesday, December 18, 2024 at 4:04:43 PM UTC-7 Jesse Mazer wrote:

On Wed, Dec 18, 2024 at 4:58 PM Alan Grayson <[email protected]> wrote:

On Wednesday, December 18, 2024 at 2:42:39 PM UTC-7 Brent Meeker wrote:

On 12/17/2024 11:21 PM, Alan Grayson wrote:

       On Tuesday, December 17, 2024 at 10:16:51 PM UTC-7 Brent Meeker 
wrote:

               On 12/17/2024 7:52 PM, Alan Grayson wrote:

                        On Tuesday, December 17, 2024 at 6:57:28 PM UTC-7 
Alan Grayson wrote:

                             On Tuesday, December 17, 2024 at 2:33:46 PM 
UTC-7 Brent Meeker wrote:

                                           On 12/17/2024 9:25 AM, Alan 
Grayson wrote:

Yes, you look at it just in terms of lengths, which is what I did in the 
first pair of diagrams.  But the relativity of simultaneity is another 
way to look at the same problem, which is what I showed in my last posting.

*Another way, but not the only way. AG *

We seem to be on the same page concerning use of length contraction to 
explain the
differing results in the frames under consideration. But I remain unclear 
how the
disagreement of simultaneity can also give the same results. For example, 
suppose
from the pov of the garage frame, the car fits in the garage for sufficient 
v, with room
to spare, but the front and rear end EVENTS do not Lorentz transform into 
simultaneous
events in the car frame. Can't there be other ways for the car to fit, 
using another set 
of events which* are* simultaneous in the car frame? AG

Sure. If  the car's speed was just right, it would be the same length as 
the garage.  Then in the diagram A and B would be at the same time in the 
garage frame the car would be just the right length such that the rear of 
the car entered the garage just as the front exited the garage.  Since we 
know the car is 12 long and the garage is 10 long we can calculate the 
required speed from 10/12 =sqrt{1-v^2} which yields v=0.553 if I did the 
arithmetic right.


That would be 0.553c. So, if the front and back events in the garage frame 
are simultaneous in the car frame AND in the garage frame, 

Nobody said that the events were simultaneous in the car frame.  The car is 
contracted in the car frame.  You keep throwing shit in problem just to 
keep it going.  I'm starting to suspect you're just a troll.

Brent



*My question for you is this; when will you learn to read English? You act 
like an uneducated prick who can't read basic English. The consensus view 
in the physics community is that the solution to this problem involves 
disagreement about simultaneity. I don't see this as correct. For example, 
that's what Quentin wrote several times, mocking me, and that's what a link 
claimed, without proof, which someone posted. And even Jesse, if I read him 
correctly, claims that the result in one frame must be false if there's no 
simultaneity.*


What do you mean by "if there's no simultaneity"? What I said was that the 
prediction of the two frames would disagree about local events (a genuine 
physical contradiction) in an imaginary universe where both inertial frames 
*did* agree about simultaneity (i.e. there is no relativity of simultaneity 
like in the real-world theory of relativity) but where they still each 
predicted objects in the other frame would experience length contraction.

Anyway, it'd be helpful if you'd go back to that last comment of mine and 
answer my questions about whether you understand how classical space/time 
plots work, and also whether you understand that in relativity you have to 
use the Lorentz transformation on the coordinates of an event labeled in 
one frame to find the "same event" in a different frame, with the result 
that any *specific* pair of events on the front & back of the car that are 
simultaneous in the car frame are non-simultaneous in the garage frame 
(although in the garage frame you can find a *different* pair of events on 
the front & back of the car which are simultaneous in the garage frame but 
not the car frame, which is what Brent was talking about).

Jesse


*Yeah, I understand that we must use the LT to transform between inertial 
frames. AG*


I wasn't just asking about transforming between frames in general, I was 
asking if you understand that coordinates in a given frame are used to 
identify individual physical events, and the LT are then used to identify 
the coordinates of the "same event" in a different frame (this implies that 
a pair of events at the front and back of the car which are simultaneous in 
some frame *cannot* be simultaneous in any other frame that's moving 
relative to that one, at least not in a problem with only one spatial 
dimension). 

Also, you didn't address my question about if you understand how 
*classical* plots of position vs. time work, which I asked because I was 
trying to figure out what aspect of my comment about worldlines in 
relativity you couldn't follow. Here again was my question, in a post you 
didn't reply to:

'Can you try to be specific about what aspect of it you find hard to 
follow? First of all, do you feel you have a good grasp of plots of 
position vs. time in classical physics, where there is no disagreement 
about simultaneity or time or distance intervals, or do you need a 
refresher on the classical graphs before trying to follow the relativistic 
ones? Do you understand for example why if we had a classical graph with 
various lines or curves representing the worldlines of objects, with time 
on the vertical axis and position on the horizontal axis, then if we wanted 
to know the position of all the objects at a particular time, that would 
involve drawing a horizontal line of fixed time coordinate (a classical 
line of simultaneity, which doesn't change from one frame to another) and 
seeing where the horizontal line intersects with the worldlines of the 
objects?'
 

* but if the events of measuring front and back in garage frame, for a 
perfect fit, why do we care how they transform in the car frame, since the 
problem is completely solved using length contraction?*


I have already explained the point here is pedagogical (in several other 
posts that you never responded to--I think it would help the discussion if 
you would respond to every post where I ask you a question, instead of 
taking a sporadic approach). Here was what I said in the first post where I 
made this point:

'The reason physicists bother to talk about a hypothetical scenario like 
this is pedagogical, they want to get students to think about situations 
where the perspective of different frames might *seem* to lead to real 
physical contradictions, and then looking at it more closely they'll 
understand how the "real" physical predictions in relativity are always 
about local events, and that by considering different definitions of 
simultaneity we can show the two frames do agree about all local events on 
rulers and clocks.
Do you disagree with my point that if different frames *didn't* have 
differing definitions of simultaneity, it would be impossible for the two 
frames to disagree about whether the car or garage was shorter without this 
leading to conflicting predictions about local events, like what the clocks 
mounted to front and back of the car will read at the instant they pass 
clocks attached to the front and back of the garage?'

And in a later post, I elaborated on why differences in simultaneity are 
critical to avoiding contradictory predictions about localized physical 
events:

'In an imaginary alternative physics where different frames had no 
disagreement about simultaneity but different observers still all believed 
the length contraction equation should apply in their frame, then this 
would be a genuine paradox/physical contradiction, because different frames 
would end up making different predictions about local events. Think about 
it this way--if there were no disagreement about simultaneity, there could 
be no disagreement about the *order* of any two events (this would be the 
case even if observers predicted moving clocks run slow like in 
relativity). But if observer #1 thinks the car is shorter than the garage, 
he will predict the event A (the back of the car passing the front of the 
garage) happens before event B (the front of the car reaches the back of 
the garage), and if observer #2 thinks the car is longer than the garage, 
he will predict B happens before A. If there were no disagreement about 
simultaneity this would lead them to different predictions about readings 
on synchronized clocks at the front and back of the car/garage at the 
moment of those events, specifically whether the clock at A would show a 
greater or lesser time than the clock at B.'

Jesse


*Jesse; in the near future I will try to address each of the issues you've 
raised, but for now let me just say I don't understand how to resolve this 
issue, and my tentative pov is that relativity just isn't correct. Listen; 
we start in a rest frame of a car which is longer than a garage. and have 
no problem asserting that it won't fit. And that's how things seem from 
both entities with physical observers. So far so good. Now we imagine the 
car in motion and apply length contraction in both frames and we get 
opposite results; namely, that in the car's frame, it won't fit in the 
garage, but in the garage frame it does fit, and the fits gets easier as 
the car's velocity increases. If I imagine a real car and a real garage, 
from one frame it doesn't fit, the car's frame, and from the other frame, 
the garage, it does fit. So, if intially the car doesn't fit, from the pov 
of both physical entities should I expect contrary results when the car is 
in motion?  Maybe so. But I still can't wrap my head around the alleged 
claim, that the observed reality will be frame dependent. I mean, how can 
two observers in different frames, looking at a real car, disagree on what 
they see? Incidentally, I just noticed that in one of Brent's recent posts 
with two diagrams, he says there is a disagreement about simultanaeity, but 
I am not sure if he's referring to comparing the two frames, and when I 
interpreted this as his comparison, he got angry, denying my 
interpretation. My bias is that the frames should agree (on what a bird's 
eye observer would see?), but does that require disagreement about 
simultaneity? AG*

why is it claimed that the solution to the problem, whatever it is, depends 
on disagreements of simultaneous events, when there are none? And if we get 
different results for fitting in the garage, where, for example, the car 
never fits, is there anything about this result that implies something 
contradictory or paradoxical? AG

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