On 1/25/2025 6:34 PM, Alan Grayson wrote:


On Saturday, January 25, 2025 at 6:47:22 PM UTC-7 Jesse Mazer wrote:

    On Sat, Jan 25, 2025 at 8:07 PM Alan Grayson <[email protected]>
    wrote:

        On Monday, December 9, 2024 at 2:01:28 PM UTC-7 Brent Meeker
        wrote:

            >
            > Nothing odd about dilation and contraction when you know
            its cause.
            > But what is odd is the fact that each frame sees the result
            > differently -- that the car fits in one frame, but not
            in the other --
            > and you see nothing odd about that, that there's no
            objective reality
            > despite the symmetry. AG

            The facts are events in spacetime.  There's an event F at
            which the
            front of the car is even with the exit of the garage and
            there's an
            event R at which the rear of the car is even with the
            entrance to the
            garage.  If R is before F we say the car fitted in the
            garage. If R is
            after F we say the car did not fit.  But if F and  R are
            spacelike, then
            there is no fact of the matter about their time order. 
            The time order
            will depend on the state of motion.

            Brent


        Jesse; it's the last two of Brent's sentences that I find
        ambiguous. What
        does he mean?


    What about them do you find ambiguous?


    He's just saying that if there's a spacelike separation between
    the events F and R (as there was in his numerical example), then
    you can find a frame where R happens after F (as is true in the
    car frame where the car doesn't fit), and another frame where F
    happens after R (as is true in the garage frame where the car does
    fit).

*
*
*What does he mean by "But if F and  R are spacelike, then there is no fact of the matter about their time order."? (What you wrote above?) *
Yes.  Just what Jesse wrote above.  It means the two events were so close together in time and distant in space that something would have to travel faster than light to be at both of them.*

*
*More important I just realized that in the frame of car fitting, the events F and R aren't simultaneous, so how does one apply disagreement on simultaneity when one starts with two events which are NOT simultaneous? AG*
That's why you should talk about events being spacelike...the relativistic analogue of simultaneous.   Spacelike is an /*invariant*/ concept.  It */does not/* depend the reference frame. If it's true in one frame, it's true in all.  But the time order of two spacelike events is frame dependent.  So the same two spacelike events F and R can be both simultaneous and not simultaneous.   Changing from one state of motion to another can reverse their time order. They can be in the order F before R and also R before F. There will be some intermediate state of motion that makes the two spacelike events simultaneous in that particular reference frame.  The car/garage paradox doesn't depend on that.

Brent

        I also wonder what happens when we transform in the
        reverse direction from the pov of simultaneity, from the car
        frame to the
         garage frame? TY, AG


    Brent didn't mention a direction in which the transformation is
    being taken, but regardless of whether you start with the
    coordinates of F and R in the garage frame and transform to the
    car frame, or start with the coordinates of F and R in the car
    frame and transform to the garage frame, you get the same answers
    about what the coordinates of these F and R are in each frame. For
    instance if you start with the coordinates x,t of F in the garage
    frame and apply the LT


*But don't you have to start with two events which are simultaneous in one frame, to get a disagreement in simultaneity in a second frame, but F and R are not simultaneous in car fitting frame?  AG*

    to get the coordinates x',t' of F in the car frame, then apply the
    LT to x',t' (this time using a velocity of -0.8c rather than +0.8c
    since the garage frame is moving in the -x direction as seen in
    the car frame) you will get back the original coordinates x,t for
    the garage frame.

    Jesse

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