On Tue, 2006-07-11 at 17:06 -0400, Chris Toshok wrote:
> On Wed, 2006-07-12 at 02:28 +0530, Ritesh Khadgaray wrote:
> > 
> > out of curiosity, the first patch reads through the list
> > and this patch, return if any one of the token is equal, anf not any
> > following it.
> > 
> > Would the below not be better ?
> > 
> >         for (i = 0; i < tokens_len; i ++)
> >                 if (tokens[i] != token)
> >                         break; 
> 
> That will free the token in the list.
> 

Oops. Einstein moment. Thanks :)


-- 
Ritesh Khadgaray
LinuX N Stuff
Ph: +919822394463
Eat Right, Exercise, Die Anyway.

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