On Wed, 2006-07-12 at 02:28 +0530, Ritesh Khadgaray wrote: > > out of curiosity, the first patch reads through the list > and this patch, return if any one of the token is equal, anf not any > following it. > > Would the below not be better ? > > for (i = 0; i < tokens_len; i ++) > if (tokens[i] != token) > break;
That will free the token in the list. Chris _______________________________________________ Evolution-hackers mailing list Evolution-hackers@gnome.org http://mail.gnome.org/mailman/listinfo/evolution-hackers