No problem. Another thought occurred to me: since XPath takes an XMLNode object, I wonder if you can leave decoding on, and just pass it the root node of the WebService response? Not sure if that's an XMLNode object, but it seems like it would be since the internals of the SOAPCall end up using the XML object.
Hope that doesn't confuse things for you. I'd be curious to know the answer to that though. :) -----Original Message----- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of Merrill, Jason Sent: Thursday, May 18, 2006 3:21 PM To: Flashcoders mailing list Subject: RE: [Flashcoders] .NET and XML Web services Ah - looks like xfactorstudios didn't pay their ISP fees this month, the site is down. Thanks anyway! I can easily test this theory out when I have a second (busy day today) - if Xpath can accept XML as a string - but I'm also kind of highly doubting it as well. Thanks for all your help. Jason Merrill Bank of America Learning and Organizational Effectiveness Technology Solutions -----Original Message----- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of Tom Lee Sent: Thursday, May 18, 2006 3:12 PM To: 'Flashcoders mailing list' Subject: RE: [Flashcoders] .NET and XML Web services I can't find docs for xfactor XPath, but a quick look at the XPath class seems to show that you need to pass an XML Node. Doesn't look like it accepts a string. -----Original Message----- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of Merrill, Jason Sent: Thursday, May 18, 2006 2:51 PM To: Flashcoders mailing list Subject: RE: [Flashcoders] .NET and XML Web services ...unless in your comment about Xpath maybe what you were saying is instead of loading into a Flash XML object: //this is my guess as to how it would work //after the WSDL was loaded and the call made //(myXML is the SOAP webservice pure XML return) myXML = xmlWebServiceResult; var theXMLObject:XML = new XML(); theXMLObject.load(myXML); XPath.selectNodes(theXMLObject, "the/path/string") I do can just do this as a string instead: myXML = xmlWebServiceResult; XPath.selectNodes(myXML, "the/path/string"); Right? Or no? Maybe XPath *can* take an XML string instead of an XML object. Thanks! Jason _______________________________________________ [email protected] To change your subscription options or search the archive: http://chattyfig.figleaf.com/mailman/listinfo/flashcoders Brought to you by Fig Leaf Software Premier Authorized Adobe Consulting and Training http://www.figleaf.com http://training.figleaf.com _______________________________________________ [email protected] To change your subscription options or search the archive: http://chattyfig.figleaf.com/mailman/listinfo/flashcoders Brought to you by Fig Leaf Software Premier Authorized Adobe Consulting and Training http://www.figleaf.com http://training.figleaf.com _______________________________________________ [email protected] To change your subscription options or search the archive: http://chattyfig.figleaf.com/mailman/listinfo/flashcoders Brought to you by Fig Leaf Software Premier Authorized Adobe Consulting and Training http://www.figleaf.com http://training.figleaf.com _______________________________________________ [email protected] To change your subscription options or search the archive: http://chattyfig.figleaf.com/mailman/listinfo/flashcoders Brought to you by Fig Leaf Software Premier Authorized Adobe Consulting and Training http://www.figleaf.com http://training.figleaf.com
