...let's hope you don't get any floating point numbers or you'll flunk CS 101...
--- In [email protected], "Seth Caldwell" <[EMAIL PROTECTED]> wrote: > > Not to be harsh, but this sounds like something my first cs course in > college would have had as an assignment or problem in a homework set. > > This has nothing to do with flex. > > > > var A:Array = [15,15,35,35,35,35, 35,55,55,75,95,105,115,115,115]; > var B:Array = new Array(); > > Var maxrun:Number=0; > > for each(var n:Number in A) > > { > > if(!B[n]) B[n]=1; > > else B[n]++; > > if(B[n]>maxrun) maxrun=B[n]; > > } > > > > From: [email protected] [mailto:[EMAIL PROTECTED] On > Behalf Of jmfillman > Sent: Wednesday, January 23, 2008 2:26 PM > To: [email protected] > Subject: [flexcoders] Array Item Counting > > > > I have an array with several dynamically populated numbers. The array > is then sorted to group identical values together. > > Let's say my array contains the following:[15,15,35,35,35,35, > 35,55,55,75,95,105,115,115,115] > > What I need to do is get a count of each number, and determine the > highest frequency, in the above example, the number 35 is listed 4 > times, so I would need to set a variable = 4. I've been playing around > with a for loop. Since I have 168 potential matches (15, 35, 55, 75, > 95, all the way to 2875) incrementing by 20, that's a bit excessive for > a bunch of if statements. It seems like a nested for loop could do > this, but I can't figure it out. Maybe there's an even better way I > haven't considered. > > for (var rowCount:int=0;rowCount < arrayRows.length;rowCount++){ > var my15:int; > if (arrayRows[rowCount].row == 15){ > my15 = my15+1; > trace (my15); > } > } >
