Sparkaround wrote:
> It seemed that this example code make the problem more clear.
> The program will never exit if I press 'a' !
Oops, my bad -- since your widget derives from Fl_Widget,
I don't think it responds to FL_ENTER/LEAVE/FOCUS by default,
so the code needs a small modification to react to the FL_KEYDOWN event
(see below).
I don't think this will affect your problem of slowness to respond,
but it should make it react to the KEYDOWN event..
#include <FL/Fl.H>
#include <FL/Fl_Widget.H>
#include <FL/Fl_Double_Window.H>
#include <FL/fl_draw.H>
#include <stdlib.h> // exit()
#define DELAY 0.001
class Test_Draw: public Fl_Widget {
public:
Test_Draw(int x, int y, int w, int h, char *l=0):Fl_Widget(x,y,w,h,l) {
}
void draw() {
static int d=0;
d++;
fl_rectf(x(),y(), (int) d%w(), (int)d%h(), d%255,d%255,d%255);
}
int handle(int e) {
int ret = Fl_Widget::handle(e);
switch (e) {
case FL_ENTER: // must handle these to get FL_KEYDOWN
case FL_LEAVE:
case FL_FOCUS:
ret = 1;
break;
case FL_KEYDOWN:
ret = 1;
printf("KEYDOWN: %d\n", Fl::event_key());
if ( Fl::event_key('a') ) exit(0);
break;
}
return(ret);
}
};
Test_Draw *t;
static void update(void *) {
t->redraw();
Fl::repeat_timeout(DELAY, update, 0);
}
int main(int argc, char **argv) {
Fl_Double_Window w(200,200,Fl::w()/2, Fl::h()/2);
//Fl_Window w(200,200,Fl::w()/2, Fl::h()/2);
t = new Test_Draw(0,0,w.w(),w.h());
w.end();
w.show(argc, argv);
Fl::add_timeout(DELAY, update, 0);
return(Fl::run());
}
> I have to stop the program with 'ESC'. It take me about ten seconds to press
> 'ESC' before the program exited.
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