I need to put some content into columns dynamically with XSL-FO. I've a template called AnswerKeySection which can have one or more AnswerKeyQuestions. Now I need them arranged like 3 AnswerKeyQuestions into 1 row. So I want something like
Question1 Question2 Question3
Question4 Question5 Question6
Question7 Question8 Question9
instead of
Question1
Question2
Question3
Question4
Question5
Question6
Question7
Question8
Question9
I'm wondering whether this is possible, I tried to use column-count property but didn't notice nay difference.
I'm posting my code from XSL for a better understanding. Any help would be greatly appreciated.
Thanks,
Bharathi
<xsl:template match="AnswerKeySection">
<fo:block keep-together="always" white-space-colla pse = "false">
<xsl:if test="not(position()=last())">
<xsl:attribute name="break-after">page</xsl:attribute>
</xsl:if>
<xsl:apply-templates select="SectionName"/>
<xsl:apply-templates select="SectionHeader"/>
<xsl:apply-templates select="AnswerKeyQuestion"/>
</fo:block>
</xsl:template>
<xsl:template match="AnswerKeyQuestion">
<fo:table table-layout="fixed" width="100%" keep-together="always">
<fo:table-column column-width="proportional-column-width(1)"/>
<fo:table-body space-after.optimum="5pt" keep-together="always">
<fo:table-row padding-bottom="0.5em">
<fo:table-cell>
<xsl:apply-templates select="QuestionInfo"/>
</fo:table-cell>
</fo:table-row>
<fo:table-row keep-with-previous="always">
<fo:table-cell>
<xsl:apply-templates select="Notes"/>
</fo:table-cell>
</fo:table-row>
<fo:table-row keep-with-previous="always">
<fo:table-cell>
<xsl:apply-templates select="Blank"/>
</fo:table-cell>
</fo:table-row>
<fo:table-row keep-with-previous="always">
<fo:table-cell>
<xsl:apply-templates select="Order"/>
;
</fo:table-cell>
</fo:table-row>
<fo:table-row keep-with-previous="always">
<fo:table-cell>
<xsl:apply-templates select="TrueFalse"/>
</fo:table-cell>
; </fo:table-row>
</fo:table-body>
</fo:table>
</xsl:template>
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