On Tue, Apr 13, 2021 at 09:11:55PM +0200, [email protected] wrote:
> @Waldek: I mean, you said that I = \int_a^b f(x)dx = ad_gauss(f, a, b,
> 1.0e-12, 25), but looking at the use of h (third parameter) in the code I
> would say that I = ad_gauss(f, a, b-a, 1.0e-12, 25). Ric
Right, thanks for correction.
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Waldek Hebisch
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