I think I would rewrite [Oo]([Ff][Ff][Ii][Cc][Ee])? as ([Oo][Ff][Ff][Ii][Cc][Ee])?
but, pardon my ignorance, won't an "i" at the end of the regex make it catch either case? Meryll -----Original Message----- From: Uri Guttman [mailto:[EMAIL PROTECTED] Sent: Monday, January 07, 2008 2:06 PM To: Fun with Perl Subject: regex of the month (decade?) ^([Pp]([Oo][Ss][Tt])?[.\s]*[Oo]([Ff][Ff][Ii][Cc][Ee])?[.\s]*[Bb][Oo] [Xx])|[Pp][Oo]([Bb]|[Xx]|[Dd][Rr][Aa][Ww][Ee][Rr]|[Ss][Tt][Oo][Ff][Ff] [Ii][Cc][Ee]|[ ][Bb][Xx]|[Bb][Oo][Xx])|[Pp][/][Oo]|[Bb]([Xx]|[Oo][Xx]| [Uu][Zz][Oo][Nn])|[Aa]([Pp][Aa][Rr][Tt][Aa][Dd][Oo]|[Pp][Tt][Dd][Oo]) the challenge: itemize the stupidities. the case issue is only 1! i don't want to even post the 'spec' unless asked for it. i saw this on usenet today. enjoy!! uri -- Uri Guttman ------ [EMAIL PROTECTED] -------- http://www.stemsystems.com --Perl Consulting, Stem Development, Systems Architecture, Design and Coding- Search or Offer Perl Jobs ---------------------------- http://jobs.perl.org
