https://gcc.gnu.org/g:244d02bb288a07f3252fc9ed38675b93a9a91225

commit r15-1512-g244d02bb288a07f3252fc9ed38675b93a9a91225
Author: Steve Baird <ba...@adacore.com>
Date:   Thu May 23 17:11:42 2024 -0700

    ada: Predefined arithmetic operators incorrectly treated as directly visible
    
    In some cases, a predefined operator (e.g., the "+" operator for an
    integer type) is incorrectly treated as being directly visible when
    it is not. This can lead to both accepting operator uses that should
    be rejected and also to incorrectly rejecting legal constructs as ambiguous
    (for example, an expression "Foo + 1" where Foo is an overloaded function 
and
    the "+" operator is directly visible for the result type of only one of
    the possible callees).
    
    gcc/ada/
    
            * sem_ch4.adb (Is_Effectively_Visible_Operator): A new function.
            (Check_Arithmetic_Pair): In paths where Add_One_Interp was
            previously called unconditionally, instead call only if
            Is_Effectively_Visible_Operator returns True.
            (Check_Boolean_Pair): Likewise.
            (Find_Unary_Types): Likewise.

Diff:
---
 gcc/ada/sem_ch4.adb | 22 +++++++++++++++++++++-
 1 file changed, 21 insertions(+), 1 deletion(-)

diff --git a/gcc/ada/sem_ch4.adb b/gcc/ada/sem_ch4.adb
index 1175a34df218..dfeff02a011b 100644
--- a/gcc/ada/sem_ch4.adb
+++ b/gcc/ada/sem_ch4.adb
@@ -270,6 +270,18 @@ package body Sem_Ch4 is
    --  these aspects can be achieved without larger modifications to the
    --  two-pass resolution algorithm.
 
+   function Is_Effectively_Visible_Operator
+     (N : Node_Id; Typ : Entity_Id) return Boolean
+   is (Is_Visible_Operator (N => N, Typ => Typ)
+         or else
+           --  test for a rewritten Foo."+" call
+           (N /= Original_Node (N)
+             and then Is_Effectively_Visible_Operator
+                        (N => Original_Node (N), Typ => Typ))
+         or else not Comes_From_Source (N));
+   --  Return True iff either Is_Visible_Operator returns True or if
+   --  there is a reason it is ok for Is_Visible_Operator to return False.
+
    function Possible_Type_For_Conditional_Expression
      (T1, T2 : Entity_Id) return Entity_Id;
    --  Given two types T1 and T2 that are _not_ compatible, return a type that
@@ -6641,6 +6653,8 @@ package body Sem_Ch4 is
            and then (Covers (T1 => T1, T2 => T2)
                        or else
                      Covers (T1 => T2, T2 => T1))
+           and then Is_Effectively_Visible_Operator
+                      (N, Specific_Type (T1, T2))
          then
             Add_One_Interp (N, Op_Id, Specific_Type (T1, T2));
          end if;
@@ -6670,6 +6684,8 @@ package body Sem_Ch4 is
            and then (Covers (T1 => T1, T2 => T2)
                        or else
                      Covers (T1 => T2, T2 => T1))
+           and then Is_Effectively_Visible_Operator
+                      (N, Specific_Type (T1, T2))
          then
             Add_One_Interp (N, Op_Id, Specific_Type (T1, T2));
 
@@ -6713,6 +6729,8 @@ package body Sem_Ch4 is
            and then (Covers (T1 => T1, T2 => T2)
                        or else
                      Covers (T1 => T2, T2 => T1))
+           and then Is_Effectively_Visible_Operator
+                      (N, Specific_Type (T1, T2))
          then
             Add_One_Interp (N, Op_Id, Specific_Type (T1, T2));
          end if;
@@ -7086,6 +7104,7 @@ package body Sem_Ch4 is
                T := Any_Modular;
             end if;
 
+            --  test Is_Effectively_Visible_Operator here ???
             Add_One_Interp (N, Op_Id, T);
          end if;
       end Check_Boolean_Pair;
@@ -7615,7 +7634,8 @@ package body Sem_Ch4 is
                then
                   null;
 
-               else
+               elsif Is_Effectively_Visible_Operator (N, Base_Type (It.Typ))
+               then
                   Add_One_Interp (N, Op_Id, Base_Type (It.Typ));
                end if;
             end if;

Reply via email to